Codeforces Round #734 (Div. 3) A~D1 個人題解
|\) 貪心， 很容易想到最小化 \(|c_1 - c_2|\) 等於 \(0\) 或 \(1\) ...
原文：Codeforces Round #594 (Div. 2) D1 - The World Is Just a Programming Task （貪心）
思路：枚舉換的位置i，j 然后我們要先判斷改序列能否完全匹配 如果可以 那我們就需要把差值最大的位置換過來 然后直接判斷就行 View Code ...
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