思路:用一個字典統計出每個數字出現的次數,然后遍歷字典,找到只出現一次的
# -*- coding:utf-8 -*-
class Solution:
# 返回[a,b] 其中ab是出現一次的兩個數字
def FindNumsAppearOnce(self, array):
# write code here
dic = {}
for i in array:
if i in dic:
dic[i] += 1
else:
dic[i] = 1
res = []
for i in dic:
if dic[i] == 1:
res.append(i)
return res