Container With Most Water

    題意是有個高度數組，就相當於隔板的高度，求數組中任意兩隔板間盛水的最大量。隔板間的距離與較低隔板的高度乘積即為盛水的容量。

int maxArea(vector<int> &height)
{
    int capability = 0;
    size_t left = 0, right = height.size() - 1;

    while (left < right)
    {
        const int water =
            min(height[left], height[right]) * (right - left);

        if (water > capability) capability = water;

        if (height[left] < height[right])
        {
            ++left;
        }
        else
        {
            --right;
        }
    }

    return capability;
}