在cocos2d中使tilemap地圖有無限循環的效果

首先我們要根據所需的地圖制作兩張tilemap地圖，然后根據當前的position判斷是目前是哪一張地圖進行合理的顯示。

附主要代碼：

-(void) setViewPointCenter:(CGPoint)position
{     
    CGSize winSize = [[CCDirector sharedDirector] winSize];
    if (-1*self.position.x>((_tilemap.mapSize.width * _tilemap.tileSize.width)+_tilemap.position.x-winSize.width-1.0)) {
        if ((-1*self.position.x>(_tilemap1.mapSize.width * _tilemap1.tileSize.width)+_tilemap1.position.x-winSize.width-1.0))
        {
            _tilemap.position = ccp(_tilemap1.position.x+(_tilemap1.mapSize.width * _tilemap1.tileSize.width),0);
        }
        else {
            CGPoint mapPosition = [self tilePosFromLocation:_spiderman.position tileMap:_tilemap1];
            int x = MAX(position.x, winSize.width / 2);
            int y = MAX(position.y, winSize.height / 2);
            x = MIN(x, (_tilemap1.mapSize.width * _tilemap1.tileSize.width)+_tilemap1.position.x
                    - winSize.width / 2);
            y = MIN(y, (_tilemap1.mapSize.height * _tilemap1.tileSize.height)
                    - winSize.height/2);
            CGPoint actualPosition = ccp(x, y);
            
            CGPoint centerOfView = ccp(winSize.width/2, winSize.height/2);
            CGPoint viewPoint = ccpSub(centerOfView, actualPosition);
            self.position = viewPoint;
        }
    }
    else {
        CGPoint mapPosition = [self tilePosFromLocation:_spiderman.position tileMap:_tilemap];
        int x = MAX(position.x, winSize.width / 2);
        int y = MAX(position.y, winSize.height / 2);
        x = MIN(x, (_tilemap.mapSize.width * _tilemap.tileSize.width)+_tilemap.position.x
                - winSize.width / 2);
        y = MIN(y, (_tilemap.mapSize.height * _tilemap.tileSize.height)
                - winSize.height/2);
        CGPoint actualPosition = ccp(x, y);
        CGPoint centerOfView = ccp(winSize.width/2, winSize.height/2);
        CGPoint viewPoint = ccpSub(centerOfView, actualPosition);
        self.position = viewPoint;
        if((-1*self.position.x>(_tilemap.mapSize.width * _tilemap.tileSize.width)+_tilemap.position.x-winSize.width-1.0))
        {
            _tilemap1.position = ccp(_tilemap.position.x+(_tilemap.mapSize.width * _tilemap.tileSize.width),0);
        }
    }
}

整個思想還是比較簡單，就是根據目前的地圖將第二章地圖放到目前地圖的后面緊跟，注意tilemap大小的計算：

_tilemap1.mapSize.width * _tilemap1.tileSize.width