js 將兩個數組里的對象一一對應合並

ar obj1 = [{ "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53 }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5 }]; var obj2 = [{ "price": "6666" }, { "price": "8888" }]; 

上面是兩個數組里面有對個對象，需求是把obj2中的每個價格和obj1里面的一一合並成一個對象，最后生成一個新的數組，是這種形式

[{
  "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53, "price": "6666" }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5, "price": "8888" }]

解決辦法：

合並數組或者對象在數組或對象前面加...，是es6的新寫法，然后數組的map方法會返回數組.

var obj1 = [{ "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53 }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5 }]; var obj2 = [{ "price": "6666" }, { "price": "8888" }]; var obj = obj1.map((item,index) => { return {...item, ...obj2[index]}; }); console.log(obj);