js 将两个数组里的对象一一对应合并

ar obj1 = [{ "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53 }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5 }]; var obj2 = [{ "price": "6666" }, { "price": "8888" }]; 

上面是两个数组里面有对个对象，需求是把obj2中的每个价格和obj1里面的一一合并成一个对象，最后生成一个新的数组，是这种形式

[{
  "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53, "price": "6666" }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5, "price": "8888" }]

解决办法：

合并数组或者对象在数组或对象前面加...，是es6的新写法，然后数组的map方法会返回数组.

var obj1 = [{ "id": 980550455852, "model": "XQG70-S1208FW", "color": "白", "invStatusName": "正品", "bactualQty": 10947, "brealyQty": 11000, "bavailQty": 53 }, { "id": 980550566221, "model": "XQB70-C3006", "color": "灰", "invStatusName": "正品", "bactualQty": 11, "brealyQty": 6, "bavailQty": -5 }]; var obj2 = [{ "price": "6666" }, { "price": "8888" }]; var obj = obj1.map((item,index) => { return {...item, ...obj2[index]}; }); console.log(obj);