斐波那契數列———輸出前n項_C/C++

#include<stdio.h>

int main() { int n; scanf("%d",&n); int a[n]; int i; //構造斐波那契數列 
    if(n==1){ a[0] = 1; }else{ a[0] = 1; a[1] = 1; } for(i=2;i<n;i++){ a[i] = a[i-1] + a[i-2]; } //輸出斐波那契數列 
    for(i=0;i<n;i++) printf("%d ",a[i]); return 0; }