我的LeetCode解題報告索引 題目鏈接 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
題意: 給定 個字符串a, b,求b在a中出現的次數。要求可以是不連續的,但是b在a中的順序必須和b以前的一致。 思路: 類似於數字分解的題目。dp i j 表示:b的前j個字符在a的前i個字符中出現的次數。 似乎這種表示方法司空見慣,但是一開始我還真沒能搞懂如何去遞推。事情的真相是: 如果a i b j 則 dp i j dp i j dp i j 如果a i b j 則 dp i j dp i ...
2012-11-16 11:26 0 4384 推薦指數:
我的LeetCode解題報告索引 題目鏈接 Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
題目: Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new string which ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
Distinct Subsequences Given a string S and a string T, count the number of distinct subsequences of T in S. A subsequence of a string is a new ...
問題 給出字符串S和T,計算S中為T的不同的子序列的個數。 一個字符串的子序列是一個由該原始字符串通過刪除一些字母(也可以不刪)但是不改變剩下字母的相對順序產生的一個新字符串。如,ACE是ABCD ...
Given a string S and a string T, count the number of distinct subsequences of S which equals T. A subsequence of a string is a new string which ...
Given a string S, count the number of distinct, non-empty subsequences of S . Since the result may be large, return the answer modulo 10^9 + 7. ...
Max Sum Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & %I64u Subm ...