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原文鏈接:https://blog.csdn.net/jerrytomcat/article/details/82351605
1. group by 的解釋:
對哪個字段 ( 哪幾個字段)進行分組。
2. group by 的用法:
select 字段 from 表 where 條件 group by 字段1(,字段2,字段3)
select 字段 from 表 group by 字段1(,字段2,字段3)having 過濾條件
ps:where 是先過濾,再分組;having 是分組后再過濾
3. group by 的案例:
- 創建student表:
create table student(
id, int
name,varchar(20)
grade,varchar(20)
salary,varchar(20)
);
- 向student表中插入數據:
insert into student values(1,'zhang','A',1500)
insert into student values(2,'wang','B',3000)
insert into student values(3,'liu','A',1500)
insert into student values(4,'sun','A',3500)
insert into student values(5,'wu','C',2000)
insert into student values(6,'xu','D',2500)
- student 表的結果:
| id | name | grade | salary |
| 1 | zhang | A | 1500 |
| 2 | wang | B | 3000 |
| 1 | zhang | A | 1500 |
| 4 | liu | A | 3500 |
| 5 | wu | C | 2000 |
| 6 | xu | D | 2500 |
- 單個字段分組
- SELECT grade FROM student
| grade |
| A |
| B |
| A |
| A |
| C |
| D |
-
- SELECT grade FROM student GROUP BY grade
| grade |
| A |
| B |
| C |
| D |
- 多個字段分組
- SELECT name,SUM(salary) FROM student GROUP BY name,grade
- 按照名字和成績划分,查看相同名字下的工資總和sum()是聚合函數
- PS: 這里把名字和成績看成一個整體,只要是name相同,grade不同,就是兩條記錄
- SELECT name,SUM(salary) FROM student GROUP BY name,grade
| name | sum(salary) |
| zhang | 3000 |
| wang | 3000 |
| liu | 3500 |
| wu | 2000 |
| xu | 2500 |
- Group By中Select指定的字段限制
- select后的字段:
- 要么就要包含在Group By語句的后面,作為分組的依據;
- 要么就要被包含在聚合函數中。
- 錯誤:
- SELECT name, salary FROM student GROUP BY name
- select 后的字段 salary 不在 group by 后面,所以salary無法顯示全部值。
- 正確1:
- SELECT name, salary FROM student GROUP BY name , salary
- select 后的字段 name,salary 都包含在group by 后面,兩個字段分組。
- 正確 2:
- SELECT name,MAX(salary) FROM student GROUP BY name
- select 后的字段 salary 雖然不在 group by 后面,但是在聚合函數MAX(salary)里面,所以只會有一個值會正確。
- select后的字段:
最后: group by 的具體過程實現,字段合並,聚合函數使用,詳見https://blog.csdn.net/qq_35069223/article/details/84343961。
