Java 數組復制之clone方法


一、源碼

public class Test1 {
    public static void main(String[] args) {
        // Student[] arrs = new Student[] { new Student() { id = "22" } }; C# 可以簡寫法,Java不支持
        Student[] arrs = new Student[1];
        Student st = new Student();
        st.id = 12;
        st.name = "qwe";
        arrs[0] = st;
        Student[] arrss = arrs.clone();
        System.out.println(arrs == arrss);
        System.out.println(arrs.equals(arrss));
        arrss[0].id = 56;
        for (int i = 0; i < arrs.length; i++) {
            System.out.println(arrs[i].id + arrs[i].name);
        }
        for (int i = 0; i < arrss.length; i++) {
            System.out.println(arrss[i].id + arrss[i].name);
        }
        System.out.println("-------------自定義對象類型數組clone-------------");

        Student[] arrst1 = new Student[1];
        Student st1 = new Student();
        st1.id = 162;
        st1.name = "qkkj";
        arrst1[0] = st1;
        Student[] arrst2 = arrst1;
        System.out.println(arrst1 == arrst2);
        System.out.println(arrst1.equals(arrst2));
        arrst2[0].id = 996;
        for (int i = 0; i < arrst1.length; i++) {
            System.out.println(arrst1[i].id + arrst1[i].name);
        }
        for (int i = 0; i < arrst2.length; i++) {
            System.out.println(arrst2[i].id + arrst2[i].name);
        }
        System.out.println("-------------自定義對象類型數組= 賦值-------------");

        var arr1 = new String[] { "we", "dfeffg" };
        var arr = arr1.clone();
        System.out.println(arr1 == arr);
        System.out.println(arr1.equals(arr));
        arr[1] = "ddddddddddddddd";
        for (int i = 0; i < arr.length; i++) {
            System.out.println(arr[i]);
        }
        for (int i = 0; i < arr1.length; i++) {
            System.out.println(arr1[i]);
        }
        System.out.println("------------字符串數組clone--------------");

        var arr11 = new String[] { "we", "dfeffg" };
        var arr111 = arr11;
        System.out.println(arr111 == arr11);
        System.out.println(arr111.equals(arr11));
        arr111[1] = "ddddddddddddddd";
        for (int i = 0; i < arr11.length; i++) {
            System.out.println(arr11[i]);
        }
        for (int i = 0; i < arr111.length; i++) {
            System.out.println(arr111[i]);
        }
        System.out.println("------------字符串數組=賦值--------------");

        var arr2 = new int[] { 232, 45 };
        var arr3 = arr2.clone();
        System.out.println(arr2 == arr3);
        System.out.println(arr2.equals(arr3));
        arr3[1] = 4444;
        for (int i = 0; i < arr2.length; i++) {
            System.out.println(arr2[i]);
        }
        for (int i = 0; i < arr3.length; i++) {
            System.out.println(arr3[i]);
        }
        System.out.println("------------數字類型數組clone--------------");

        var arr4 = new int[] { 23432, 44455 };
        var arr5 = arr4;
        System.out.println(arr4 == arr5);
        System.out.println(arr4.equals(arr5));
        arr4[1] = 6666;
        for (int i = 0; i < arr4.length; i++) {
            System.out.println(arr4[i]);
        }
        for (int i = 0; i < arr5.length; i++) {
            System.out.println(arr5[i]);
        }
        System.out.println("------------數字類型數組=賦值-----------------");
    }
}

class Student {
    public int id;
    public String name;
}

二、運行結果

false
false
56qwe
56qwe
-------------自定義對象類型數組clone-------------
true
true
996qkkj
996qkkj
-------------自定義對象類型數組= 賦值-------------
false
false
we
ddddddddddddddd
we
dfeffg
------------字符串數組clone--------------
true
true
we
ddddddddddddddd
we
ddddddddddddddd
------------字符串數組=賦值--------------
false
false
232
45
232
4444
------------數字類型數組clone--------------
true
true
23432
6666
23432
6666
------------數字類型數組=賦值-----------------

三、結果分析

  1.clone復制,對於數組本身而言,它的元素是引用類型(字符串除外)的時候,本來數組每個元素中保存的就是對象的引用,所以,拷貝過來的數組自然而言也是對象的引用,所以對於數組對象元素而言,它又是淺拷貝;

  2.clone復制,對於引用類型(字符串除外),改變其中一個中的值,會影響另外一個值,相當於“淺拷貝”;

  3.clone復制,對於值類型、字符串,改變其中一個中的值,不會影響另外一個值,相當於“深拷貝”;

  4.等號復值后修改一個后會影響另一個


免責聲明!

本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。



 
粵ICP備18138465號   © 2018-2025 CODEPRJ.COM