Description
A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..., xm > another sequence Z = < z1, z2, ..., zk > is a subsequence of X if there exists a strictly increasing sequence < i1, i2, ..., ik > of indices of X such that for all j = 1,2,...,k, xij = zj. For example, Z = < a, b, f, c > is a subsequence of X = < a, b, c, f, b, c > with index sequence < 1, 2, 4, 6 >. Given two sequences X and Y the problem is to find the length of the maximum-length common subsequence of X and Y.
Input
The program input is from the std input. Each data set in the input contains two strings representing the given sequences. The sequences are separated by any number of white spaces. The input data are correct.
Output
For each set of data the program prints on the standard output the length of the maximum-length common subsequence from the beginning of a separate line.
Sample Input
abcfbc abfcab
programming contest
abcd mnp
Sample Output
4
2
0
Source
AC代碼:

1 #include<iostream> 2 #include<cstring> 3 #include<cstdio> 4 using namespace std; 5 char s1[1005],s2[1005]; 6 int l1,l2,dp[1005][1005]; 7 int main(){ 8 while(~scanf("%s%s",s1 + 1,s2 + 1)){//下標從1開始 9 l1 = strlen(s1 + 1); 10 l2 = strlen(s2 + 1); 11 for(int i = 0;i <= l2;i++)//填充第一行 12 dp[0][i] = 0; 13 for(int i = 0;i <= l1;i++)//填充第一列 14 dp[i][0] = 0; 15 for(int i = 1;i <= l1;i++) 16 for(int j = 1;j <= l2;j++){ 17 if(s1[i] == s2[j])//不理解的強烈建議畫圖看看就明白了 18 dp[i][j] = dp[i - 1][j - 1] + 1; 19 else 20 dp[i][j] = max(dp[i - 1][j],dp[i][j - 1]); 21 } 22 printf("%d\n",dp[l1][l2]); 23 } 24 return 0; 25 }