CRM客戶關系管理系統（五）

第五章、分頁功能開發

5.1.修改BaseKingAdmin和完善前段頁面顯示

現在訪問沒有注冊的model會報錯，因為基類中沒有寫list_display和list_filter。

 

 在基類中設置一個空列表就可以了

# kingadmin/admin_base.py

class BaseKingAdmin(object):

    list_display = []
    list_filter = []
　　 search_fields = []

 現在訪問沒有報錯，但是沒有顯示出數據，需要在 build_tab_row 里面添加個判斷

 

kingadmin_tags.py

@register.simple_tag
def build_table_row(obj,admin_class):
    '''生成一條記錄的html element'''

    ele = ''
    if admin_class.list_display:
        for column_name in admin_class.list_display:
            #獲取所有字段對象
            column_obj = admin_class.model._meta.get_field(column_name)
            #字段對象的choices方法，如果有choices，則get_xxx_display
            if column_obj.choices:
                column_data = getattr(obj,'get_%s_display'%column_name)()
            else:
                column_data = getattr(obj,column_name)
            td_ele = "<td>%s</td>" % column_data
            ele += td_ele
    else:
        td_ele = "<td>%s</td>"%obj
        ele += td_ele

 

 在table_obj_list.html添加一個判斷

 

（2）完善前端頁面顯示

配置了list_display的顯示所有列名，沒配置的應該顯示model name

table_obj_lsit.html

<thead
                <tr>
                    {% if admin_class.list_display %}
                        {% for column in admin_class.list_display %}
                            <th>{{ column }}</th>
                        {% endfor %}
                    {% else %}
                        <th>{% get_model_name admin_class %}</th>
                    {% endif %}
                </tr>
            </thead>

kingadmin_tags.py

@register.simple_tag
def get_model_name(admin_class):
    '''獲取表名'''
    return admin_class.model._meta.model_name.upper()

前端顯示效果

 

5.2.分頁功能開發

 django官網paginationg使用說明

 

 官網實例

 

 

 （1）kingadmin/views.py

@login_required
def table_obj_list(request, app_name, model_name):
    '''取出指定model里的數據返回給前端'''
    #拿到admin_class后，通過它找到拿到model
    admin_class = site.enable_admins[app_name][model_name]
    querysets = admin_class.model.objects.all()
    #過濾
    querysets,filter_conditions = get_filter_result(request,querysets)
    admin_class.filter_conditions = filter_conditions
    #分頁
    paginator = Paginator(querysets, 2)  
    page = request.GET.get('page')
    try:
        querysets = paginator.page(page)
    except PageNotAnInteger:
        querysets = paginator.page(1)
    except EmptyPage:
        querysets = paginator.page(paginator.num_pages)

    return render(request, 'kingadmin/table_obj_list.html',{'querysets':querysets,'admin_class':admin_class})

（2）table_obj_lsit.html

<div class="pagination">
            <span class="step-links">
                {% if querysets.has_previous %}
                    <a href="?page={{ querysets.previous_page_number }}">previous</a>
                {% endif %}

                <span class="current">
                    Page {{ querysets.number }} of {{ querysets.paginator.num_pages }}.
                </span>

                {% if querysets.has_next %}
                    <a href="?page={{ querysets.next_page_number }}">next</a>
                {% endif %}
            </span>
        </div>

這個時候訪問頁面，確實實現分頁了，但是點下一頁會報錯

 

 

因為在后台把page='2'當成過濾條件了，添加個判斷

 kingadmin/views.py

 

5.3.分頁功能優化

      Bootstrap分頁組件

 

 （1）kingadmin_tag.py

@register.simple_tag
def render_paginator(querysets):
    '''分頁'''
    ele = '''
        <ul class="pagination">
    '''
    #page_range是所有的頁，querysets.number是當前頁
    for i in querysets.paginator.page_range:
        #顯示前后三頁，abs是絕對值
        if abs(querysets.number - i) < 3:
            active = ''
            if querysets.number == i:     #如果是當前頁,class='active'
                active = 'active'
            p_ele = '''<li class="%s"><a href="?page=%s">%s</a></li>'''%(active,i,i)
            ele += p_ele
    ele += "</ul>"
    return mark_safe(ele)

（2）table_obj_list.html

 

效果：