斗地主的檢測 根據張數先拆分成多個小檢測函數,然后開始對可能的類型進行檢測。單張對子這些基礎的檢測就不必說了,
現在寫下對三帶N這種應用遞歸來獲取所有的出牌牌型和值的方式
function CardsGroupCheck_DouDiZhu.SanDai(args,laiziNum,need3Num,need2Num,need1Num,start) --需要控制,癩子不能帶王
local SaveSanDaiCards = {};
if need3Num == 0 and need2Num == 0 and need1Num == 0 then
table.insert(SaveSanDaiCards,args)
else
local targetGroup = {};
for i= start,3,-1 do
-- if args[i] == 4 and need3Num > 0 then --4個的不能拆成3個的
-- local temp = copyTab(args);
-- temp[i] = 1;
-- table.insert(temp.Group,i);
-- table.insert(temp.Group,i);
-- table.insert(temp.Group,i);
-- temp.Value = i;
-- CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum,need3Num-1,need2Num,need1Num,i));
-- else
if args[i] == 3 and need3Num > 0 then
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
table.insert(temp.Group,i);
table.insert(temp.Group,i);
temp.Value = i;
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum,need3Num-1,need2Num,need1Num,i-1));
elseif args[i] == 2 then
if need3Num > 0 then
if laiziNum > 0 then
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
table.insert(temp.Group,i);
table.insert(temp.Group,i);
temp.Value = i;
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum-1,need3Num-1,need2Num,need1Num,i-1));
end
end
if need2Num > 0 then
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
table.insert(temp.Group,i);
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum,need3Num,need2Num-1,need1Num,i-1));
end
if need1Num > 0 then
local temp = copyTab(args);
temp[i] = 1;
table.insert(temp.Group,i);
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum,need3Num,need2Num,need1Num-1,i));
end
elseif args[i] == 1 then
if need3Num > 0 then
if laiziNum >= 2 and i <= 15 then
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
table.insert(temp.Group,i);
table.insert(temp.Group,i);
temp.Value = i;
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum-2,need3Num-1,need2Num,need1Num,i-1));
end
end
if need2Num > 0 then
if laiziNum >= 1 and i <= 15 then --王不能因為一張然后補成對子
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
table.insert(temp.Group,i);
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum-1,need3Num,need2Num-1,need1Num,i-1));
end
end
if need1Num > 0 then
local temp = copyTab(args);
temp[i] = 0;
table.insert(temp.Group,i);
CardsGroupCheck_DouDiZhu.AddAll(SaveSanDaiCards,CardsGroupCheck_DouDiZhu.SanDai(temp,laiziNum,need3Num,need2Num,need1Num-1,i-1));
end
end
end
end
return SaveSanDaiCards;
end
function CardsGroupCheck_DouDiZhu.AddAll(target,st) for k, v in pairs(st or {}) do table.insert(target,v); end end
這樣我最后通過sandai函數得到的數據就是我所有的可能性,當然對多個癩子要對不同的癩子數來得到所有的集合。對於多種癩子就需要重新對癩子的個數來出。這個在遞歸的外層進行循環就可以得到所有。
