Fibonacci數列Java實現


Fibonacci數列:如是:[1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89]

f(0) = 1; f(1) = 1; f(n) = f(n-1)+f(n-2) n>1;

 1 import java.util.Arrays;
 2 
 3 public class Test {
 4 
 5     public static void main(String[] args) {
 6         Test test = new Test();
 7         int n = 15;
 8         int[] fibonacciArray = new int[n]; 
 9         for (int i = 0; i < n; i++) {
10             fibonacciArray[i] = test.fibonacci(i);//將n處的值存入數組中
11         }
12         System.out.println(Arrays.toString(fibonacciArray));
13     }
14     
15     //遞歸求解n處的值
16     private int fibonacci(int n){
17         if(n==0||n==1){
18             return 1;
19         }
20         else if(n>1){
21             return fibonacci(n-1)+fibonacci(n-2);
22         }
23         else{
24             return 0;
25         }
26     }
27 }

輸出:
   [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610]
 1 //普通循環求解
 2 int n1 = 15;
 3 for(int i = 0; i<n1; i++){
 4     if(i==0 || i==1){
 5     fibnacciArray1[i] = 1;
 6     }
 7     else{
 8         fibnacciArray1[i] = fibnacciArray1[i-1]+fibnacciArray1[i-2];
 9     }
10 }
11 System.out.println(Arrays.toString(fibnacciArray1));

輸出:
    [1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610]

 


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