[POJ 1004] Financial Management C++解題


 
 
Financial Management
Time Limit: 1000MS   Memory Limit: 10000K
Total Submissions: 116320   Accepted: 53669

Description

Larry graduated this year and finally has a job. He's making a lot of money, but somehow never seems to have enough. Larry has decided that he needs to grab hold of his financial portfolio and solve his financing problems. The first step is to figure out what's been going on with his money. Larry has his bank account statements and wants to see how much money he has. Help Larry by writing a program to take his closing balance from each of the past twelve months and calculate his average account balance.

Input

The input will be twelve lines. Each line will contain the closing balance of his bank account for a particular month. Each number will be positive and displayed to the penny. No dollar sign will be included.

Output

The output will be a single number, the average (mean) of the closing balances for the twelve months. It will be rounded to the nearest penny, preceded immediately by a dollar sign, and followed by the end-of-line. There will be no other spaces or characters in the output.

Sample Input

100.00
489.12
12454.12
1234.10
823.05
109.20
5.27
1542.25
839.18
83.99
1295.01
1.75

Sample Output

$1581.42

翻譯:

我就不一句一句翻譯了,題目的大意就是Larry想要計算她一年12個月的余額平均值。

然后,是12行,分別輸入一年12個月的余額,輸出它們的平均值,前面帶“$”符合。

 

解決思路

這也是一道練習C語言語法的水題,

源碼

 1 /*
 2 poj 1000
 3 version:1.0
 4 author:Knight
 5 Email:S.Knight.Work@gmail.com
 6 */
 7 
 8 #include<cstdio>
 9 using namespace std;
10 int main(void)
11 {
12     int i;
13     double Tmp, Sum;
14     Sum = 0.0;
15     for (i=0; i<12; i++)
16     {
17         scanf("%lf", &Tmp);
18         Sum += Tmp;
19     }
20     printf("$%.2lf\n", Sum / 12);
21     return 0;
22 }

 

 


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