update語句更新多條記錄, 標記下

轉 ---  的兩篇內容

update多條Select出來的數據

好多朋友喜歡用游標解決此問題，但是執行速度狂慢！
其實解決起來很簡單了：
 
先來個簡單的：
把FLowER的Am_employee表的email,dept_id,ext_no多條數據按emp_no對應update到EmpBaseInfo表中：
update EmpBaseInfo 
set email=b.Mail_account,dept_id=b.dept_code,ext_no=b.ext_no
from flower.flower.dbo.am_employee b
where b.emp_no=EmpBaseInfo.emp_no
 
復雜一點的：
多表select，並將結果對應插入到指定的表中：
 
update EmpBaseInfo
set Job_Rank=b.level_number
from flower.flower.dbo.am_employee a,flower.flower.dbo.am_level b,flower.flower.dbo.am_approver_level c
where a.emp_id=c.emp_id and b.level_number=c.level_number and a.emp_no=EmpBaseInfo.emp_no
 
 
取別名的：
update x
set Job_Rank=b.level_number
from flower.flower.dbo.am_employee a,flower.flower.dbo.am_level b,flower.flower.dbo.am_approver_level c,EmpBaseInfo x
where a.emp_id=c.emp_id and b.level_number=c.level_number and a.emp_no=x.emp_no

 

--另外一種方式: 臨時表

偶用臨時表來解決
1、創建臨時表#temp_1
SELECT card_id,sum(card_cost) as 'sum_cost'
INTO #tmp_1
FROM pos_t_vip_cost
GROUP by card_id
go
2、更新表pos_t_vip_info記錄
UPDATE pos_t_vip_info,#tmp_1
SET pos_t_vip_info.card_amount = #tmp_1.sum_cost
WHERE pos_t_vip_info.card_id = #tmp_1.card_id
go
3、刪除臨時表
DROP TABLE #tmp_1
go

 

以上是參考資料

 

update [StormPlatform120316].[dbo].[t_Assessment]
set Developers = le.DevelopmentPrincipal
from  [StormPlatform120316].[dbo].[t_Assessment] a left join [StormPlatform0623].[dbo].[t_LeaderEvaluation] le on a.RequirementApplyID = le.RequirementApplyID and le.createtime in (select max(createtime) from [StormPlatform0623].[dbo].[t_LeaderEvaluation] group by RequirementApplyID)
where a.Developers = ''

Mysql的update語句

2010-04-24 20:31 mysql update from 子查詢mssql 子查詢更新

update log set uin= b.uin
from log a,logs b
where a.accountuin = b.accountuin

mysql 不支持 update 子查詢更新

找了半天資料 終於搞定了...

update `log` a inner join `logs` b on a.`accountuin` = b.`accountuin`
set a.`uin` = b.`uin` where a.`accountuin` = b.`accountuin`

這樣就能 將查詢出來的字段批量更新過去了...

 

//delete的聯合查詢

Update 


Update XXX set XXX where 這種寫法大家肯定都知道，才發現update和delete居然支持inner join的update方式，這個在表間關聯來做更新和刪除操作非常有用. 

列子: 




Sql代碼 
update tb_User   
set pass=''  
from tb_User usr   
inner join tb_Address addr on usr.nAddressFK = addr.nAddressID   
where usr.id=123  

update tb_User 
set pass='' 
from tb_User usr 
inner join tb_Address addr on usr.nAddressFK = addr.nAddressID 
where usr.id=123update的格式是 

update t1 set t1.name=’Liu’ from t1 inner join t2 on t1.id = t2.tid 




MYSQL，ACCESS 寫法如下: 




Sql代碼 
UPDATE mem_world AS mw1 INNER JOIN mem_world  AS  mw2     
ON  mw1.parentid = mw2.wid    
SET mw1.level = mw2.level     
WHERE mw2.baseid = 107     
AND  mw2.parentid = 0     
AND  mw2.size > 1;  

UPDATE mem_world AS mw1 INNER JOIN mem_world  AS  mw2  
ON  mw1.parentid = mw2.wid 
SET mw1.level = mw2.level  
WHERE mw2.baseid = 107  
AND  mw2.parentid = 0  
AND  mw2.size > 1; 

on是表連接的篩選條件 
就是說，表連接后，會產生一個類似於臨時的視圖這么一個東西 
where是從這個臨時的視圖中篩選數據的 
所以，你首先要搞清，你的所謂的2個條件屬於哪一種 




Delete 




delete 語句也是類似 

delete from t1 from t1 inner join t2 on t1.id = t2.tid 

注意藍色部分。 

mysql: 


Sql代碼 
DELETE mwb FROM  mem_world_building AS mwb INNER JOIN mem_world AS mw   
ON mwb.wid = mw.wid   
where mw.type between 11 and 15    
and baseid = 107    
and mw.parentid <> 0    
and  mw.size > 1;  

DELETE mwb FROM  mem_world_building AS mwb INNER JOIN mem_world AS mw 
ON mwb.wid = mw.wid 
where mw.type between 11 and 15 
and baseid = 107 
and mw.parentid <> 0 
and  mw.size > 1;  
下面是ORACLE的: 


Sql代碼 
DELETE TABLE1 where exists ( select 1 from table2 where and table1.khid=table2.khid and FWDWID=8);  

DELETE TABLE1 where exists ( select 1 from table2 where and table1.khid=table2.khid and FWDWID=8); 



Sql代碼 
DELETE TABLE1 where KHID exists ( select KHID from table2 where FWDWID=8)  

DELETE TABLE1 where KHID exists ( select KHID from table2 where FWDWID=8)