(Java) LeetCode 139. Word Break —— 單詞拆分
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determine ...
原文：[LeetCode] 139. Word Break 單詞拆分
Given anon emptystringsand a dictionarywordDictcontaining a list ofnon emptywords, determine ifscan be segmented into a space separated sequence of one or more dictionary words. Note: The same word in ...
2018-03-05 15:05 0 946 推薦指數：
相關推薦
[LeetCode] 139. Word Break 拆分詞句
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, determ ...
leetcode139.單詞拆分
給定一個非空字符串 s 和一個包含非空單詞列表的字典 wordDict，判定 s 是否可以被空格拆分為一個或多個在字典中出現的單詞。 思路分析： （1）比較容易想到的解法是，從字符串 s 開頭處開始匹配，若匹配到字典里的字符串，則繼續匹配剩下的字符串。這樣遞歸下去，直到找到一個可行的序列或嘗試 ...
[LeetCode] 140. Word Break II 單詞拆分II
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word ...
[LeetCode] Word Break II 拆分詞句之二
Given a non-empty string s and a dictionary wordDict containing a list of non-empty words, add spaces in s to construct a sentence where each word ...
[leetcode]Word Break @ Python
原題地址：https://oj.leetcode.com/problems/word-break/ 題意： Given a string s and a dictionary of words dict, determine if s can be segmented ...
Word Break leetcode java
words. For example, given s = "leetcode", dict = ["le ...
[Leetcode] Word Break II
Given a string s and a dictionary of words dict, add spaces in s to construct a sentence where each word is a valid dictionary word. Return all ...