Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list ...
Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list whose elements may also be integers or other lists. D ...
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Given a nested list of integers, return the sum of all integers in the list weighted by their depth. Each element is either an integer, or a list ...
Reverse a linked list from position m to n. Do it in one-pass. Note: 1 ≤ m ≤ n ≤ length of list. Example: 很奇怪為何沒有倒置鏈表之一,就來了這個倒置鏈表之二,不過猜 ...
Given a nested list of integers, implement an iterator to flatten it. Each element is either an integer, or a list -- whose elements may also ...
Given a linked list, return the node where the cycle begins. If there is no cycle, return null. To represent a cycle in the given linked list, we ...
Given four lists A, B, C, D of integer values, compute how many tuples (i, j, k, l) there are suc ...
Given a collection of candidate numbers (candidates) and a target number (target), find all uniqu ...
Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list. Example ...
題目描述 給定一個鏈表,返回鏈表開始入環的第一個節點。 如果鏈表無環,則返回 null。 說明:不允許修改給定的鏈表。 進階: 你是否可以不用額外空間解決此題? 解題思路 分為三步: 首先判斷是否存在環,利用快慢指針法,從頭節點開始快指針每次走兩步 ...