315. Count of Smaller Numbers After Self
of smaller elements to the right of nums[i]. Exampl ...
原文：[leetcode] Count of Smaller Numbers After Self
題目： 分析：很顯然不能用時間復雜度為O N 的暴力窮舉法，下面先給出一個運行時間為 ms的AC答案： 上面的答案雖然AC了，但若原始海量數據本身是降序排列時，再運行時間也為O N ，下面給出運用樹狀數組 Binary Indexed Tree Fenwick tree 的解法，使時間復雜度將為O NlgN ，樹狀數組的相關知識可參考博客樹狀數組. 最后給出線段樹 segment tree 的解法 ...
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of smaller elements to the right of nums[i]. Example: ...
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