C++ STL用string類的時候 編譯器提示 error: no viable overloaded ‘=’，等於號不能重載
關鍵代碼就是那句賦值
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if(s1_len > s2_len) for(int i = 1; i <= s1_len - s2_len; i++) s2 = '0' + s2; ... |
然后編譯器報錯：
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main.cpp:41:10: error: no viable overloaded '='
s2 = s2 + "0"; ~~ ^ ~~~~~~~~ /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/string:1330:19: note: candidate function not viable: 'this' argument has type 'const string' (aka 'const basic_string<char, char_traits<char>, allocator<char> >'), but method is not marked const basic_string& operator=(const basic_string& __str); ^ /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/string:1337:45: note: candidate function not viable: 'this' argument has type 'const string' (aka 'const basic_string<char, char_traits<char>, allocator<char> >'), but method is not marked const _LIBCPP_INLINE_VISIBILITY basic_string& operator=(const value_type* __s) {return assign(__s);} ^ /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/../include/c++/v1/string:1338:19: note: candidate function not viable: 'this' argument has type 'const string' (aka 'const basic_string<char, char_traits<char>, allocator<char> >'), but method is not marked const basic_string& operator=(value_type __c); ^ |
我用的是Xcode的terminal-tools里的g++編譯