Java基礎練習——讀心術(撲克牌魔術——21張撲克牌)--代碼簡化版
將重復代碼封裝成一個方法,達到簡化代碼的目的
話不多說,直接上代碼!😎😎😎
歡迎大佬對代碼進行優化,魔術原理請自行百度“21張撲克牌”(本文最后附帶表演手法圖片)。
代碼
import java.util.ArrayList;
import java.util.Collections;
import java.util.Scanner;
public class CardMagic {
public static int count = 0;//用來統計重復詢問觀眾的次數,第三次詢問之后
public static void main(String[] args) {
//1.准備54張牌
//新建一個集合存儲54張牌並打亂順序
ArrayList<String> pokers = new ArrayList<>();
//直接定義兩個數組並賦值,一個存四種花色,一個存13張牌的值(3,4,5,6,7,8,9,10,J,Q,K,A,2)
String[] kind = {"♥","♠","♦","♣"};
String[] number = {"3","4","5","6","7","8","9","10","J","Q","K","A","2"};
//先存大王小王到pokers集合中
pokers.add("大王");
pokers.add("小王");
//組裝兩個集合的數據,生成帶花色的52張牌(可以用普通for循環,也可以用增強for循環foreach)
for (int i = 0; i < kind.length; i++) {
for (int j = 0; j < 13; j++) {
pokers.add(kind[i]+number[j]);
}
}
System.out.println("這里有54張牌:"+pokers);//順序打印
//洗牌--打亂pokers集合里的元素順序
Collections.shuffle(pokers);//打亂順序
//再新建一個集合,用來存儲隨機拿出的21張牌(偽隨機:其實是拿出前21張牌,但是pokers集合是隨機打亂順序的,所以每次運行程序,拿出的前21張牌也就不一樣且亂序了)
ArrayList<String> list21 = new ArrayList<>();
for (int i = 0; i < 21; i++) {
list21.add(pokers.get(i));
}
//打印出這21張牌
System.out.println("隨機取出21張撲克牌並打亂順序:");
System.out.println(list21);
System.out.println("請選擇任意一張撲克牌,並記住它。【輸入小寫字母'y'繼續,輸入其他任意字符結束游戲!】");
Scanner scanner1 = new Scanner(System.in);
if (scanner1.nextLine().equals("y")){
System.out.println("系統將這21張撲克牌均分為3疊,請等待...");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
}else {
System.exit(-1);
}
//定義3個集合,每個集合存儲7張牌
ArrayList<String> card1 = new ArrayList<>();
ArrayList<String> card2 = new ArrayList<>();
ArrayList<String> card3 = new ArrayList<>();
for (int i = 0; i < 7; i++) {
card1.add(list21.get(i));
}
for (int i = 7; i < 14; i++) {
card2.add(list21.get(i));
}
for (int i = 14; i < 21; i++) {
card3.add(list21.get(i));
}
reorder(1,card1,card2,card3);
//判斷輸入
Scanner scanner2 = new Scanner(System.in);
int a = scanner2.nextInt();
reorder(a,card1,card2,card3);
//判斷輸入
Scanner scanner3 = new Scanner(System.in);
int b = scanner3.nextInt();
reorder(b,card1,card2,card3);
//判斷輸入
Scanner scanner4 = new Scanner(System.in);
int c = scanner4.nextInt();
reorder(c,card1,card2,card3);
System.out.println("好了,稍等片刻!讓我猜猜你記住的是什么牌......");
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
System.out.println("真相永遠只有一個,你選的牌是"+card2.get(3)+"!");
System.out.println("什么?你說我是運氣好?不!這是“魔法”!");
}
public static void reorder(int a,ArrayList<String> card1,ArrayList<String> card2,ArrayList<String> card3){
ArrayList<String> list21New = new ArrayList<>();
count++;
if (a==1){
for (int i = 0; i < 7; i++) {
list21New.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card3.get(i));
}
}else if (a==2){
for (int i = 0; i < 7; i++) {
list21New.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card2.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card3.get(i));
}
}else {
for (int i = 0; i < 7; i++) {
list21New.add(card1.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card3.get(i));
}
for (int i = 0; i < 7; i++) {
list21New.add(card2.get(i));
}
}
card1.clear();
card2.clear();
card3.clear();
for (int i = 0; i < 21; i++) {
card1.add(list21New.get(i));
i++;
card2.add(list21New.get(i));
i++;
card3.add(list21New.get(i));
}
if (count<4){
System.out.println("第1疊:"+card1);
System.out.println("第2疊:"+card2);
System.out.println("第3疊:"+card3);
System.out.println("請告訴我你記住的牌在第幾疊~如果在第1疊請輸入數字1;如果在第2疊請輸入數字2;如果在第3疊請輸入數字3");
System.out.println("請輸入:");
}
}
}
運行結果
其中一次運行結果:開始我記住的就是黑桃9!😲
魔術表演步驟
值得一提的是,將21張撲克牌分成3組的具體操作,應該是:
將21張撲克牌拿在手上,按順序,從左到右依次發牌,每發3次算一輪,一共發七輪,發完就會產生3疊牌,每疊7張!😎😎😎
歡迎評論區討論😁😁😁希望多多點贊,哈哈~