C++ string轉時間戳

若配置文件中存在一個過期時間，需要與當前時間比較配置是否過期需要將配置時間和當前時間進行比較

C中存在ctime類，

//用time()取得當前時間 (秒數), 利用localtime() 轉換成struct tm 再利用mktime()將struct tm轉換成原來的秒數。
#include <time.h>
main(){
    time_t timep;
    struct tm *p;
    time(&timep);
    printf("time() : %d \n", timep);
    p = localtime(&timep);
    timep = mktime(p);
    printf("time()->localtime()->mktime():%d\n", timep);
}

另外還有將string類型的設定時間轉換為unix時間戳

#include <stdio.h> 
#include <memory.h>
#include <iostream>  
#include <ctime>
#include <string>
 
  
time_t strTime2unix(std::string timeStamp)  
{  
    struct tm tm;  
    memset(&tm, 0, sizeof(tm));  
      
    sscanf(timeStamp.c_str(), "%d-%d-%d %d:%d:%d",   
           &tm.tm_year, &tm.tm_mon, &tm.tm_mday,  
           &tm.tm_hour, &tm.tm_min, &tm.tm_sec);  
  
    tm.tm_year -= 1900;  
    tm.tm_mon--;  
  
    return mktime(&tm);  
}  
  
int main()  
{  
    std::string str = "2017-04-14 16:41:40";  
    time_t t = strTime2unix(str);
    std::cout << t << std::endl;  
    std::cout << ctime(&t) << std::endl;  
  
    return 0;  
}   

參考:http://c.biancheng.net/cpp/html/145.html:https://blog.csdn.net/shine_journey/article/details/70173947