最近做騰訊微博的demo，服務器返回的時間戳（timestamp），怎么把Int型的時間戳轉成時間呢？
java時間戳精確到毫秒，騰訊微博返回時間戳為秒，需注意。
import java.sql.Timestamp;
import java.text.ParseException;
import java.text.SimpleDateFormat;
public class GetTimeUtil {
public static String getDate(String month,String day){
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");//24小時制
java.util.Date d = new java.util.Date(); ;
String str = sdf.format(d);
String nowmonth = str.substring(5, 7);
String nowday = str.substring(8,10 );
String result = null;
int temp = Integer.parseInt(nowday)-Integer.parseInt(day);
switch (temp) {
case 0:
result="今天";
break;
case 1:
result = "昨天";
break;
case 2:
result = "前天";
break;
default:
StringBuilder sb = new StringBuilder();
sb.append(Integer.parseInt(month)+"月");
sb.append(Integer.parseInt(day)+"日");
result = sb.toString();
break;
}
return result;
}
public static String getTime(int timestamp){
SimpleDateFormat sdf=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
String time= null;
try {
java.util.Date currentdate = new java.util.Date();//當前時間
long i = (currentdate.getTime()/1000-timestamp)/(60);
System.out.println(currentdate.getTime());
System.out.println(i);
Timestamp now = new Timestamp(System.currentTimeMillis());//獲取系統當前時間
System.out.println("now-->"+now);//返回結果精確到毫秒。
String str = sdf.format(new Timestamp(IntToLong(timestamp)));
time = str.substring(11, 16);
String month = str.substring(5, 7);
String day = str.substring(8,10 );
System.out.println(str);
System.out.println(time);
System.out.println(getDate(month, day));
time =getDate(month, day)+ time;
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return time;
}
//java Timestamp構造函數需傳入Long型
public static long IntToLong(int i){
long result = (long)i;
result*=1000;
return result;
}
public static void main(String[] args) {
int timestamp = 1310457552; // 假設騰訊微博返回時間戳為秒
String time = GetTimeUtil.getTime(timestamp);
System.out.println("timestamp-->"+time);
//print timestamp-->7月12日15:59
}
}