python 謝爾賓斯基三角形的遞歸實現

import turtle

def draw(points):
    # 根據三個坐標，畫一個三角形
    t.penup()
    t.goto(points['left'])
    t.pendown()
    t.goto(points['top'])
    t.goto(points['right'])
    t.goto(points['left'])
    

def getMid(p1,p2):
    # 獲取兩個坐標的中點的坐標
    return (p1[0]+p2[0])/2,(p1[1]+p2[1])/2
    
def sierpinski(degree,points):
    draw(points)
    if degree > 0:
        # 以原三角形左邊底角坐標為起點，畫一個邊長為原來三角形邊長一半的等邊三角形
        sierpinski(degree-1,{'left':points['left'],'top':getMid(points['left'],points['top']),'right':getMid(points['left'],points['right']) })
        
        # 以原三角形左邊中點坐標為起點，畫一個邊長為原來三角形邊長一半的等邊三角形
        sierpinski(degree-1,{'left':getMid(points['left'],points['top']),'top':points['top'],'right':getMid(points['top'],points['right'])  })
        
        # 以原三角形底邊中點坐標為起點，畫一個邊長為原來三角形邊長一半的等邊三角形
        sierpinski(degree-1,{'left':getMid(points['left'],points['right']),'top':getMid(points['top'],points['right']),'right':points['right'] })
        
        
t = turtle.Turtle()
t.speed(3)  # 畫筆速度
# 初始的三角形的三個頂點
points = {'left':(-200,-100),'top':(0,200),'right':(200,-100)}
sierpinski(3,points)

turtle.done()