product 笛卡爾積
permutations 排列
combinations 組合,沒有重復
combinations_with_replacement 組合,有重復
>>> import itertools >>> for i in itertools.product('ABCD', repeat = 2): ... print i, ... ('A', 'A') ('A', 'B') ('A', 'C') ('A', 'D') ('B', 'A') ('B', 'B') ('B', 'C') ('B', 'D') ('C', 'A') ('C', 'B') ('C', 'C') ('C', 'D') ('D', 'A') ('D', 'B') ('D', 'C') ('D', 'D') >>> for i in itertools.permutations('ABCD', 2): ... print i, ... ('A', 'B') ('A', 'C') ('A', 'D') ('B', 'A') ('B', 'C') ('B', 'D') ('C', 'A') ('C', 'B') ('C', 'D') ('D', 'A') ('D', 'B') ('D', 'C') >>> for i in itertools.combinations('ABCD', 2): ... print i, ... ('A', 'B') ('A', 'C') ('A', 'D') ('B', 'C') ('B', 'D') ('C', 'D') >>> for i in itertools.combinations_with_replacement('ABCD', 2): ... print i, ... ('A', 'A') ('A', 'B') ('A', 'C') ('A', 'D') ('B', 'B') ('B', 'C') ('B', 'D') ('C', 'C') ('C', 'D') ('D', 'D')
轉載自:http://www.tuicool.com/articles/vIRryi