python之自動化連連看腳本-第一關不動-小記

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僅供學習python之用，勿用做商業用途。運行環境為1920*1080屏幕，python3.7，win7，谷歌瀏覽器版本 75.0.3770.100。

參考https://www.cnblogs.com/reader/p/10111777.html及https://baijiahao.baidu.com/s?id=1618385402903335091&wfr=spider&for=pc。

感謝先輩提供的優秀思路。

連連看游戲鏈接：http://www.4399.com/flash/80972.htm#search3

下面直接貼上代碼。

# -*- coding:utf-8 -*-


from win32 import win32gui
import time
from PIL import ImageGrab, Image
import numpy as np
import operator
from pymouse import PyMouse
import win32gui


class GameAssist:

    def __init__(self, wdname):
        """初始化"""

        # 取得窗口句柄
        self.hwnd = win32gui.FindWindow(0, wdname)
        if not self.hwnd:
            print("窗口找不到，請確認窗口句柄名稱：【%s】" % wdname )
            exit()

        # 窗口顯示最前面
        win32gui.SetForegroundWindow(self.hwnd)

        # 小圖標編號矩陣
        self.im2num_arr = []

        # 主截圖的左上角坐標和右下角坐標
        self.scree_left_and_right_point = (577, 289, 1043, 599)
        # 小圖標寬高
        self.im_width = 39

        # PyMouse對象，鼠標點擊
        self.mouse = PyMouse()

    def screenshot(self):
        """屏幕截圖"""

        # 1、用grab函數截圖，參數為左上角和右下角左標
        # image = ImageGrab.grab((417, 257, 885, 569))
        image = ImageGrab.grab(self.scree_left_and_right_point)
        # 2、分切小圖
        # exit()
        image_list = {}
        offset = self.im_width  # 39

        # 8行12列
        for x in range(8):
            image_list[x] = {}
            for y in range(12):
                # print("show",x, y)
                # exit()
                top = x * offset
                left = y * offset
                right = (y + 1) * offset
                bottom = (x + 1) * offset

                # 用crop函數切割成小圖標，參數為圖標的左上角和右下角左邊
                im = image.crop((left, top, right, bottom))
                # 將切割好的圖標存入對應的位置
                image_list[x][y] = im

        return image_list

    def image2num(self, image_list):
        """將圖標矩陣轉換成數字矩陣"""

        # 1、創建全零矩陣和空的一維數組
        arr = np.zeros((10, 14), dtype=np.int32)    # 以數字代替圖片
        image_type_list = []

        # 2、識別出不同的圖片，將圖片矩陣轉換成數字矩陣
        for i in range(len(image_list)):
            for j in range(len(image_list[0])):
                im = image_list[i][j]

                # 驗證當前圖標是否已存入
                index = self.getIndex(im, image_type_list)

                # 不存在image_type_list
                if index < 0:
                    image_type_list.append(im)
                    arr[i + 1][j + 1] = len(image_type_list)
                else:
                    arr[i + 1][j + 1] = index + 1

        print("圖標數：", len(image_type_list))

        self.im2num_arr = arr
        return arr

    # 檢查數組中是否有圖標,如果有則返回索引下表
    def getIndex(self,im, im_list):
        for i in range(len(im_list)):
            if self.isMatch(im, im_list[i]):
                return i

        return -1

    # 漢明距離判斷兩個圖標是否一樣
    def isMatch(self, im1, im2):

        # 縮小圖標，轉成灰度
        image1 = im1.resize((20, 20), Image.ANTIALIAS).convert("L")
        image2 = im2.resize((20, 20), Image.ANTIALIAS).convert("L")

        # 將灰度圖標轉成01串,即系二進制數據
        pixels1 = list(image1.getdata())
        pixels2 = list(image2.getdata())

        avg1 = sum(pixels1) / len(pixels1)
        avg2 = sum(pixels2) / len(pixels2)
        hash1 = "".join(map(lambda p: "1" if p > avg1 else "0", pixels1))
        hash2 = "".join(map(lambda p: "1" if p > avg2 else "0", pixels2))

        # 統計兩個01串不同數字的個數
        match = sum(map(operator.ne, hash1, hash2))

        # 原作者郭靖愕然閥值設為10，實測400位數字，50合適
        return match < 50

    # 判斷矩陣是否全為0
    def isAllZero(self, arr):
        for i in range(1, 9):
            for j in range(1, 13):
                if arr[i][j] != 0:
                    return False
        return True

    # 是否為同行或同列且可連
    def isReachable(self, x1, y1, x2, y2):
        # 1、先判斷值是否相同
        if self.im2num_arr[x1][y1] != self.im2num_arr[x2][y2]:
            return False

        # 1、分別獲取兩個坐標同行或同列可連的坐標數組
        list1 = self.getDirectConnectList(x1, y1)
        list2 = self.getDirectConnectList(x2, y2)
        # print(x1, y1, list1)
        # print(x2, y2, list2)

        # exit()

        # 2、比較坐標數組中是否可連
        for x1, y1 in list1:
            for x2, y2 in list2:
                if self.isDirectConnect(x1, y1, x2, y2):
                    return True
        return False

    # 獲取同行或同列可連的坐標數組
    def getDirectConnectList(self, x, y):

        plist = []
        for px in range(0, 10):
            for py in range(0, 14):
                # 獲取同行或同列且為0的坐標
                if self.im2num_arr[px][py] == 0 and self.isDirectConnect(x, y, px, py):
                    plist.append([px, py])

        return plist

    # 是否為同行或同列且可連
    def isDirectConnect(self, x1, y1, x2, y2):
        # 1、位置完全相同
        if x1 == x2 and y1 == y2:
            return False

        # 2、行列都不同的
        if x1 != x2 and y1 != y2:
            return False

        # 3、同行
        if x1 == x2 and self.isRowConnect(x1, y1, y2):
            return True

        # 4、同列
        if y1 == y2 and self.isColConnect(y1, x1, x2):
            return True

        return False

    # 判斷同行是否可連
    def isRowConnect(self, x, y1, y2):
        minY = min(y1, y2)
        maxY = max(y1, y2)

        # 相鄰直接可連
        if maxY - minY == 1:
            return True

        # 判斷兩個坐標之間是否全為0
        for y0 in range(minY + 1, maxY):
            if self.im2num_arr[x][y0] != 0:
                return False
        return True

    # 判斷同列是否可連
    def isColConnect(self, y, x1, x2):
        minX = min(x1, x2)
        maxX = max(x1, x2)

        # 相鄰直接可連
        if maxX - minX == 1:
            return True

        # 判斷兩個坐標之間是否全為0
        for x0 in range(minX + 1, maxX):
            if self.im2num_arr[x0][y] != 0:
                return False
        return True

    # 點擊事件並設置數組為0
    def clickAndSetZero(self, x1, y1, x2, y2):
        # print("click", x1, y1, x2, y2)

        # (299, 251, 768, 564)
        # 原理：左上角圖標中點 + 偏移量
        p1_x = int(self.scree_left_and_right_point[0] + (y1 - 1)*self.im_width + (self.im_width / 2))
        p1_y = int(self.scree_left_and_right_point[1] + (x1 - 1)*self.im_width + (self.im_width / 2))

        p2_x = int(self.scree_left_and_right_point[0] + (y2 - 1)*self.im_width + (self.im_width / 2))
        p2_y = int(self.scree_left_and_right_point[1] + (x2 - 1)*self.im_width + (self.im_width / 2))

        time.sleep(0.1)
        #原作者郭靖愕然用的click方法，實測click為雙擊，press單擊
        self.mouse.press(p1_x, p1_y)
        time.sleep(0.1)
        self.mouse.press(p2_x, p2_y)

        # 設置矩陣值為0
        #while self.im2num_arr[x1][y1-1]!=0
        #上面都是0沒有圖標，就置矩陣值為0
            
        self.im2num_arr[x1][y1] = 0
        self.im2num_arr[x2][y2] = 0

        print("消除：(%d, %d) (%d, %d)" % (x1, y1, x2, y2))
        # exit()

    # 程序入口、控制中心
    def start(self):

        # 1、先截取游戲區域大圖，然后分切每個小圖
        image_list = self.screenshot()

        # 2、識別小圖標，收集編號
        self.image2num(image_list)

        print(self.im2num_arr)

        # 3、遍歷查找可以相連的坐標
        while not self.isAllZero(self.im2num_arr):
            for x1 in range(1, 9):
                for y1 in range(1, 13):
                    if self.im2num_arr[x1][y1] == 0:
                        continue

                    for x2 in range(1, 9):
                        for y2 in range(1, 13):
                            # 跳過為0 或者同一個
                            if self.im2num_arr[x2][y2] == 0 or (x1 == x2 and y1 == y2):
                                continue
                            if self.isReachable(x1, y1, x2, y2):
                                self.clickAndSetZero(x1, y1, x2, y2)


if __name__ == "__main__":
    # wdname 為連連看窗口的名稱，必須寫完整
    wdname = '寵物連連看經典版2,寵物連連看經典版2小游戲,4399小游戲 www.4399.com - Google Chrome'

    demo = GameAssist(wdname)
    demo.start()