1. 資源競爭
當多個同時執行的線程需要同時對全局變量進行寫讀操作時,容易出現資源競爭的問題,導致運行結果出現多種情況。以下面的例子進行說明:
private static CancellationTokenSource cs = new CancellationTokenSource(); private static int num = 5; private static object obj = new object(); static void Main(string[] args) { Console.WriteLine("Main Start...."); Task t1 = Task.Factory.StartNew(Test); Task t2 = Task.Factory.StartNew(Test); Task.WaitAll(new Task[] { t1, t2 }); cs.Dispose(); Console.WriteLine("Main end...."); Console.ReadLine(); } static void Test() { while (!cs.IsCancellationRequested) //是否調用Cancel { Console.WriteLine("TaskId {0} Excute other code....num is {1}",Task.CurrentId,num); if(num == 5){ Thread.Sleep(50); //為了方便觀察,添加延時 num++; Console.WriteLine("TaskId {0} and Num is {1}", Task.CurrentId, num); if (!cs.IsCancellationRequested) { cs.Cancel(); //取消操作 } } } }
大多數情況,運行結果如下:
Main Start....
TaskId 1 Excute other code....num is 5
TaskId 2 Excute other code....num is 5
TaskId 2 and Num is 6
TaskId 1 and Num is 7
Main end....
任務1 首先運行至Thread.Sleep(50),等待50ms,cpu開始調度任務2運行至Thread.Sleep(50)。 接着任務1 運行num++, 並往控制台輸出結果num=6,然后任務2運行num++, 並往控制台輸出num=7。但有時也會出現下面這種結果:
Main Start....
TaskId 1 Excute other code....num is 5
TaskId 2 Excute other code....num is 5
TaskId 2 and Num is 7
TaskId 1 and Num is 7
Main end....
任務1 首先運行至Thread.Sleep(50),等待50ms,cpu開始調度任務2運行至Thread.Sleep(50)。接着任務1 運行num++,cpu馬上開始調度任務2運行num++,並往控制台輸出num=7,最后調度任務1往控制台輸出num=7。
解決方式:只需加上線程鎖lock, 便只會出現第一種運行結果,如下:
static void Test() { while (!cs.IsCancellationRequested) //是否調用Cancel { Console.WriteLine("TaskId {0} Excute other code....num is {1}",Task.CurrentId,num); if(num == 5){ Thread.Sleep(50); //為了方便觀察,添加延時 lock (obj) //只有一個線程可以操作 { num++; Console.WriteLine("TaskId {0} and Num is {1}", Task.CurrentId, num); } if (!cs.IsCancellationRequested) { cs.Cancel(); //取消操作 } } } }
2.線程死鎖
至少有2個線程被掛起,等待對方解鎖,線程將無限等待下去。
private static int num = 5; private static object obj1 = new object(); private static object obj2 = new object(); static void Main(string[] args) { Console.WriteLine("Main Start...."); Parallel.Invoke(LockTest1, LockTest2); Console.WriteLine("Main end...."); Console.ReadLine(); } static void LockTest1() { lock(obj1){ lock(obj2){ Console.WriteLine("LockTest1 is running"); } } } static void LockTest2() { lock (obj2) { lock (obj1) { Console.WriteLine("LockTest2 is running"); } } }
運行結果:
Main Start....
LockTest1 is running
LockTest2 is running
Main end....
看似正常,但這段程序在極少數的情況下,會出現死鎖。例如CPU先運行LockTest1()中lock(obj1), 馬上又運行LockTest2()中lock(obj2),這時LockTest1()會等待obj2 解鎖,而LockTest2()會等待obj1解鎖 ,形成死鎖。
解決方式:在設計程序時,考慮好鎖定的順序,或者定義鎖定超時。