js—去除重復的數

js—去除重復的數

方法一：

let arr =[1,2,2,2,3,4,5,5,6,6,7,8]; let newArr = [] outer :for (let i=0;i<arr.length;i++) { for (let j=0;j<newArr.length;j++) { if (arr[i]===newArr[j]) { continue outer;//終止名字為outer的循環
 } } newArr.push(arr[i]) } console.log(newArr)

方法二，用indexof：

let arr =[1,2,2,2,3,4,5,5,6,6,7,8]; let a=[] for(let i=0;i<arr.length;i++){ if(a.indexOf(arr[i]) == -1){ a.push(arr[i]) } } console.log(a)

 用include去重：

let arr =[1,2,2,2,3,4,5,5,6,6,7,8,2]; let a=[] for(let i=0;i<arr.length;i++){ if(a.includes(arr[i])==false){ a.push(arr[i]) } } console.log(a)

用集合去重：

let arr =[1,2,2,2,3,4,5,5,6,6,7,8,2]; let s1=new Set(arr) console.log(s1) let arr2=[...s1] console.log(arr2)