ElasticSearch master 選舉


es的master選舉機制是相當任性的也是最簡單有效的,比較版本大小,排序,然后選第一個,是不是相當任性

整個選舉過程

  private DiscoveryNode findMaster() {
        logger.trace("starting to ping");
        List<ZenPing.PingResponse> fullPingResponses = pingAndWait(pingTimeout).toList();//通過ping來獲得存在形同cluster_name活的節點 
        if (fullPingResponses == null) {
            logger.trace("No full ping responses");
            return null;
        }
        if (logger.isTraceEnabled()) {
            StringBuilder sb = new StringBuilder();
            if (fullPingResponses.size() == 0) {
                sb.append(" {none}");
            } else {
                for (ZenPing.PingResponse pingResponse : fullPingResponses) {
                    sb.append("\n\t--> ").append(pingResponse);
                }
            }
            logger.trace("full ping responses:{}", sb);
        }

        final DiscoveryNode localNode = transportService.getLocalNode();//獲取本地節點

        // add our selves 先判斷ping的節點中本地節點不在其中
        assert fullPingResponses.stream().map(ZenPing.PingResponse::node)
            .filter(n -> n.equals(localNode)).findAny().isPresent() == false;

        fullPingResponses.add(new ZenPing.PingResponse(localNode, null, this.clusterState()));//加入本地節點

        // filter responses
        final List<ZenPing.PingResponse> pingResponses = filterPingResponses(fullPingResponses, masterElectionIgnoreNonMasters, logger);

        List<DiscoveryNode> activeMasters = new ArrayList<>();
        for (ZenPing.PingResponse pingResponse : pingResponses) {//查看ping節點中已經有master的節點,這點可能就是 如果多個新節點加入,那么這些新節點是沒有master的只有老節點有
            // We can't include the local node in pingMasters list, otherwise we may up electing ourselves without
            // any check / verifications from other nodes in ZenDiscover#innerJoinCluster()
            if (pingResponse.master() != null && !localNode.equals(pingResponse.master())) {
                activeMasters.add(pingResponse.master());
            }
        }

        // nodes discovered during pinging
        List<ElectMasterService.MasterCandidate> masterCandidates = new ArrayList<>();
        for (ZenPing.PingResponse pingResponse : pingResponses) {
            if (pingResponse.node().isMasterNode()) {//這點代碼很容易讓人誤解 命名方法太不規范了 isMasterNode其實就是判斷當前cluster中是否包含master節點 有的話就加入
                masterCandidates.add(new ElectMasterService.MasterCandidate(pingResponse.node(), pingResponse.getClusterStateVersion()));
            }
        }

        if (activeMasters.isEmpty()) {//如果不存在活躍的master節點 就得從新選舉了
            if (electMaster.hasEnoughCandidates(masterCandidates)) { //節點足夠直接選舉
                final ElectMasterService.MasterCandidate winner = electMaster.electMaster(masterCandidates);
                logger.trace("candidate {} won election", winner);
                return winner.getNode();
            } else {//不夠的話 就返回空
                // if we don't have enough master nodes, we bail, because there are not enough master to elect from
                logger.warn("not enough master nodes discovered during pinging (found [{}], but needed [{}]), pinging again",
                            masterCandidates, electMaster.minimumMasterNodes());
                return null;
            }
        } else {//如果活躍的master節點存在 ,先判斷本地節點是否在其中 ,然后在存活的節點中判斷節點類型,比較id的大小,然后選擇最小的id作為master節點
            assert !activeMasters.contains(localNode) : "local node should never be elected as master when other nodes indicate an active master";
            // lets tie break between discovered nodes
            return electMaster.tieBreakActiveMasters(activeMasters);
        }
    }
  isMasterNode代碼
 /**
     * Can this node become master or not.
     */
    public boolean isMasterNode() {
        return roles.contains(Role.MASTER);
    }

 

 

如果存活的master集合不為空,選舉master機制

   /** selects the best active master to join, where multiple are discovered */
    public DiscoveryNode tieBreakActiveMasters(Collection<DiscoveryNode> activeMasters) {
        return activeMasters.stream().min(ElectMasterService::compareNodes).get();
    }


 /** master nodes go before other nodes, with a secondary sort by id **/
     private static int compareNodes(DiscoveryNode o1, DiscoveryNode o2) {
        if (o1.isMasterNode() && !o2.isMasterNode()) {
            return -1;
        }
        if (!o1.isMasterNode() && o2.isMasterNode()) {
            return 1;
        }
        return o1.getId().compareTo(o2.getId());
    }

 

存活集合為空 master選舉代碼

        /**
         * compares two candidates to indicate which the a better master.
         * A higher cluster state version is better
         *
         * @return -1 if c1 is a batter candidate, 1 if c2.
         */
        public static int compare(MasterCandidate c1, MasterCandidate c2) {
            // we explicitly swap c1 and c2 here. the code expects "better" is lower in a sorted
            // list, so if c2 has a higher cluster state version, it needs to come first.
            int ret = Long.compare(c2.clusterStateVersion, c1.clusterStateVersion);
            if (ret == 0) {
                ret = compareNodes(c1.getNode(), c2.getNode());
            }
            return ret;
        }
    }

 

compare方法

    public MasterCandidate electMaster(Collection<MasterCandidate> candidates) {
        assert hasEnoughCandidates(candidates);
        List<MasterCandidate> sortedCandidates = new ArrayList<>(candidates);
        sortedCandidates.sort(MasterCandidate::compare);
        return sortedCandidates.get(0);
    }

 


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