題目描述
查找當前薪水(to_date='9999-01-01')排名第二多的員工編號emp_no、薪水salary、last_name以及first_name，不准使用order by
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
CREATE TABLE `employees` (
`emp_no` int(11) NOT NULL,
`birth_date` date NOT NULL,
`first_name` varchar(14) NOT NULL,
`last_name` varchar(16) NOT NULL,
`gender` char(1) NOT NULL,
`hire_date` date NOT NULL,
PRIMARY KEY (`emp_no`));
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
輸入描述:
無
輸出描述:
| emp_no | salary | last_name | first_name |
|---|---|---|---|
| 10009 | 94409 | Peac | Sumant |
1 select e.emp_no, max(s.salary) , e.last_name, e.first_name 2 from employees e, salaries s 3 where s.to_date = '9999-01-01' and e.emp_no = s.emp_no and s.salary <> 4 (select max(salary) 5 from employees e, salaries s 6 where s.to_date = '9999-01-01' and e.emp_no = s.emp_no)