java-將評論內容過濾特殊表情emoj符號，保存到mysql中

正常操作評論，保存時，若評論內容含有特殊表情符號，后台將報錯如下：

Illegal mix of collations (utf8_general_ci,IMPLICIT) and (utf8mb4_general_ci,COERCIBLE) for operation '='; nested exception is java.sql.SQLException: Illegal mix of collations (utf8_general_ci,IMPLICIT) and (utf8mb4_general_ci,COERCIBLE) for operation '='

后來查閱資料，找到方法將其評論內容中特殊符號過濾掉，然后保存。廢話不多說，直接上代碼：

/**
     * 檢測是否有emoji字符
     * @param source
     * @return 一旦含有就拋出
     */
    public static boolean containsEmoji(String source) {
        if (StringUtils.isBlank(source)) {
            return false;
        }

        int len = source.length();

        for (int i = 0; i < len; i++) {
            char codePoint = source.charAt(i);

            if (isEmojiCharacter(codePoint)) {
                //do nothing，判斷到了這里表明，確認有表情字符
                return true;
            }
        }

        return false;
    }

    private static boolean isEmojiCharacter(char codePoint) {
        return (codePoint == 0x0) ||
                (codePoint == 0x9) ||
                (codePoint == 0xA) ||
                (codePoint == 0xD) ||
                ((codePoint >= 0x20) && (codePoint <= 0xD7FF)) ||
                ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) ||
                ((codePoint >= 0x10000) && (codePoint <= 0x10FFFF));
    }

    /**
     * 過濾emoji 或者 其他非文字類型的字符
     * @param source
     * @return
     */
    public static String filterEmoji(String source) {

        if (!containsEmoji(source)) {
            return source;//如果不包含，直接返回
        }
        //到這里鐵定包含
        StringBuilder buf = null;

        int len = source.length();

        for (int i = 0; i < len; i++) {
            char codePoint = source.charAt(i);

            if (isEmojiCharacter(codePoint)) {
                if (buf == null) {
                    buf = new StringBuilder(source.length());
                }

                buf.append(codePoint);
            } else {
            }
        }

        if (buf == null) {
            return source;//如果沒有找到 emoji表情，則返回源字符串
        } else {
            if (buf.length() == len) {//這里的意義在於盡可能少的toString，因為會重新生成字符串
                buf = null;
                return source;
            } else {
                return buf.toString();
            }
        }

    }