圖像滑動窗口 利用opencv和matlab

1.利用opencv實現圖像滑動窗口操作

功能：利用opencv實現圖像滑動窗口操作（即利用已知尺寸的窗口遍歷整幅圖像，形成許多子圖像） 
vs2015+opencv3.1 
2016.10

函數實現

#ifndef SLIDINGWND_H_ #define SLIDINGWND_H_ //簡單的滑動窗口的形成 #include<iostream> #include<opencv2\opencv.hpp> using namespace std; using namespace cv; //基於矩形窗口的圖像滑動窗口操作,返回值為滑動窗口的數目 //@src 輸入圖像 //@wnd 輸出結果 //@wndSize 滑動窗口的大小 //@ x_percent 滑動窗口在x方向步長的百分比，x_step=x_percent*wndSize.width //@ y_percent 滑動窗口在y方向步長的百分比，y_step=y_percent*wndSize.height int slidingWnd(Mat& src, vector<Mat>& wnd, Size& wndSize, double x_percent, double y_percent) { int count = 0; //記錄滑動窗口的數目 int x_step = cvCeil(x_percent*wndSize.width); int y_step = cvCeil(y_percent*wndSize.height); /*String wndName = "F:\\wnd\\"; char temp[1000];*/ int64 count1 = getTickCount(); double freq = getTickFrequency(); //利用窗口對圖像進行遍歷 for (int i = 0; i < src.cols- wndSize.width; i+=y_step) { for (int j = 0; j < src.rows- wndSize.height; j+=x_step) { Rect roi(Point(j, i), wndSize); Mat ROI = src(roi); wnd.push_back(ROI); count++; } } int64 count2 = getTickCount(); double time = (count2 - count1) / freq; cout << "Time=" << time * 100 << "ms"<<endl; cout << count << endl; return count; } 

main.cpp

#include<iostream> #include<opencv2\opencv.hpp> #include"slidingWnd.h" using namespace std; using namespace cv; void main() { String imgName = "F:\\lena_gray.jpg"; Mat src = imread(imgName); cvtColor(src, src, COLOR_RGB2GRAY); vector<Mat> wnd; int count=slidingWnd(src, wnd, Size(30, 30),0.3,0.3); imshow("src", src); waitKey(0); 

原文鏈接：http://blog.csdn.net/jiamuju84/article/details/52893320

2.matlab滑動窗口截取圖片並保存

該代碼的作用是對圖片進行滑動截取保存

clc;
clear all;

maindir = 'D:\MyDataSet\airplane\wheel\JPEGImages'; sundir = fullfile( maindir, '*.jpg' ); images = dir(sundir);% 在這個子文件夾下找后綴為jpg的文件 % 遍歷每張圖片 for j = 1 : length( images ) imagepath = fullfile( maindir,images( j ).name ) imgdata = imread( imagepath ); % 這里進行你的讀取操作 new_folder = strcat('F:\matlab\tools\output\',num2str(j)) mkdir(new_folder); %num1,num2是你要設定的矩形框長和寬 num1=375; num2=500; [m,n,ch]=size(imgdata); mm=m-num1; nn=n-num2; filenum=1; for k=1:100:mm for kk=1:100:nn B=imgdata(k:k+num1,kk:kk+num2,:) imshow(B); % file = ['.\output\',num2str(floor((k+kk-1)/10)),'.jpg']; file = [new_folder,'\',num2str(filenum),'.jpg']; filenum=filenum+1; imwrite(B,file); if (kk+num2)>=n break; end if (k+num1)>=m break; end end end end

原文鏈接：http://blog.csdn.net/run_it_faraway/article/details/76862506