浙大pat甲級題目---1012. The Best Rank (25)


To evaluate the performance of our first year CS majored students, we consider their grades of three courses only: C - C Programming Language, M - Mathematics (Calculus or Linear Algebra), and E - English. At the mean time, we encourage students by emphasizing on their best ranks -- that is, among the four ranks with respect to the three courses and the average grade, we print the best rank for each student.

For example, The grades of C, M, E and A - Average of 4 students are given as the following:

StudentID  C  M  E  A
310101     98 85 88 90
310102     70 95 88 84
310103     82 87 94 88
310104     91 91 91 91

Then the best ranks for all the students are No.1 since the 1st one has done the best in C Programming Language, while the 2nd one in Mathematics, the 3rd one in English, and the last one in average.

Input

Each input file contains one test case. Each case starts with a line containing 2 numbers N and M (<=2000), which are the total number of students, and the number of students who would check their ranks, respectively. Then N lines follow, each contains a student ID which is a string of 6 digits, followed by the three integer grades (in the range of [0, 100]) of that student in the order of C, M and E. Then there are M lines, each containing a student ID.

Output

For each of the M students, print in one line the best rank for him/her, and the symbol of the corresponding rank, separated by a space.

The priorities of the ranking methods are ordered as A > C > M > E. Hence if there are two or more ways for a student to obtain the same best rank, output the one with the highest priority.

If a student is not on the grading list, simply output "N/A".

Sample Input

5 6
310101 98 85 88
310102 70 95 88
310103 82 87 94
310104 91 91 91
310105 85 90 90
310101
310102
310103
310104
310105
999999

Sample Output

1 C
1 M
1 E
1 A
3 A
N/A

 題目大意:是一道模擬題,意思是讓我們找出每個人最佳的排名

題目思路:這道題我用的是最笨的辦法。首先定義一個結構體,存放學生id,四門成績以及最佳排名,這道題的主要目的就是填充每個學生的最佳排名變量。我主要是用map<string,student>來存儲每個學生(方便用於之后查找)然后定義四個數組分別存放四門課,對四個數組分別排名,然后針對每個待查找的學生,分別查看他們每門成績的排名,再排序,找到排名最優的。具體看代碼吧。

#include <iostream>
#include <vector>
#include <algorithm>
#include<map>
using namespace std;
int aa[2005],cc[2005],mm[2005],ee[2005];
enum subject
{
    AA=0,
    CC,
    MM,
    EE
};
struct student
{
    string id;
    int c,m,e,a;    // four garde
    int max;    //best grade
    subject symbol;
};
bool compare(int a,int b)
{
    return a>b; //升序排列,如果改為return a>b,則為降序
}
int check(int *t,int score,int n)
{
    for(int i=0;i<n;i++)
    {
        if(t[i]==score)
            return i+1;
    }
}

void getSymbol(student &i,int n)
{
    int a,c,m,e;
    int mim=1000;
    a=check(aa,i.a,n);
    c=check(cc,i.c,n);
    m=check(mm,i.m,n);
    e=check(ee,i.e,n);
    if(a<mim)
    {
        mim=a;
        i.symbol=AA;
        i.max=mim;
    }
    if(c<mim)
    {
        mim=c;
        i.symbol=CC;
        i.max=mim;
    }
    if(m<mim)
    {
        mim=m;
        i.symbol=MM;
        i.max=mim;
    }

    if(e<mim)
    {
        mim=e;
        i.symbol=EE;
        i.max=mim;
    }

}
int main()
{
    int m,n;
    int i;
    map<string,student> rank;
    subject symbol;
    string id,search;
    id.resize(7);
    search.resize(7);
    int C,M,E,A;

    int max=-1;
    scanf("%d%d",&n,&m);
    for(i=0;i<n;i++)
    {
        max=-1;
        student s;
        scanf("%s",&id[0]);
        scanf("%d%d%d",&C,&M,&E);
        A=(C+M+E)/3;
        //if(judge(aa,A,n))
            aa[i]=A;
        //if(judge(cc,C,n))
            cc[i]=C;
        //if(judge(mm,M,n))
            mm[i]=M;
        //if(judge(ee,E,n))
            ee[i]=E;
        s.a=A;s.c=C;s.e=E;s.m=M;s.id=id;

        s.max=max;
        s.symbol=symbol;
        rank[id]=s;
        //cout<<symbol<<" "<<s.max<<endl;
    }
    sort(aa,aa+n,compare);
    sort(cc,cc+n,compare);
    sort(mm,mm+n,compare);
    sort(ee,ee+n,compare);
    for(i=0;i<m;i++)
    {
        scanf("%s",&search[0]);//學會這種輸入string的辦法
        if(rank.find(search)==rank.end())
            cout<<"N/A"<<endl;
        else
        {
            getSymbol(rank[search],n);
            if(rank[search].symbol==AA)
            {
                cout<<rank[search].max<<" ";
                cout<<"A"<<endl;
            }
            else if(rank[search].symbol==CC)
            {
                cout<<rank[search].max<<" ";
                cout<<"C"<<endl;
            }
            else if(rank[search].symbol==MM)
            {
                cout<<rank[search].max<<" ";
                cout<<"M"<<endl;
            }
            else if(rank[search].symbol==EE)
            {
                cout<<rank[search].max<<" ";
                cout<<"E"<<endl;
            }
        }

    }
    return 0;
}

 


免責聲明!

本站轉載的文章為個人學習借鑒使用,本站對版權不負任何法律責任。如果侵犯了您的隱私權益,請聯系本站郵箱yoyou2525@163.com刪除。



 
粵ICP備18138465號   © 2018-2025 CODEPRJ.COM