數據結構C++ 大根堆——大根堆的應用


兩個應用實例,函數聲明 application.h :

 1 #pragma once
 2 #include "jobNode.h"
 3 
 4 //堆排序
 5 template<typename T>
 6 void heapSort(T *dataArray, int arraySize)  7 {  8     maxHeap<T> Heap;  9  Heap.initialize(dataArray, arraySize); 10     for (int i = 0; i < arraySize; i++) 11  { 12         dataArray[i] = Heap.top(); 13         cout << int(dataArray[i]) << " "; 14  Heap.pop(); 15  } 16     cout << endl; 17 } 18 
19 
20 //LPT,最長處理時間機器調度
21 void LPTschedule(jobNode *Jobs, int jobSize, int machineSize);

機器調度算法所需要的結構定義在 jobNode.h 中:

 1 #pragma once
 2 
 3 struct jobNode  4 {  5     int jobNo;  6     int Time;  7     jobNode() = default;  8     jobNode(int cNo, int cTime)  9     { jobNo = cNo; Time = cTime; } 10 
11     operator int() const
12     { return Time; } 13 }; 14 
15 
16 struct machineNode 17 { 18     int machineNo; 19     int Time; 20     machineNode() = default; 21     machineNode(int cNo, int cTime) 22     { machineNo = cNo; Time = cTime; } 23 
24     operator int() const
25     { return Time; } 26 };

應用實例的實現 application.cpp :

 1 #include <iostream>
 2 #include "jobNode.h"
 3 #include "maxHeap.h"
 4 #include "application.h"
 5 
 6 
 7 using namespace std;  8 
 9 
10 void LPTschedule(jobNode *Jobs, int jobSize, int machineSize) 11 { 12     if (jobSize <= machineSize) 13  { 14         cout << "jobSize <= machineSize" << endl; 15         return ; 16  } 17     int allTime = 0; 18     for (int k = 0; k < jobSize; k++) 19         allTime += Jobs[k].Time; 20 
21  heapSort(Jobs, jobSize); 22 
23     maxHeap<machineNode> Heap; 24     for (int i = 0; i < machineSize; i++) 25  { 26         machineNode jjj(i + 1, allTime); 27  Heap.push(jjj); 28  } 29     for (int j = 0; j < jobSize; j++) 30  { 31         machineNode machine = Heap.top(); 32  Heap.pop(); 33         cout << machine.machineNo << "號機器從 " << allTime - machine.Time 34             << "" << (allTime - machine.Time + Jobs[j].Time) << " 期間完成"
35             << j << "號任務" << endl; 36         machine.Time -= Jobs[j].Time; 37  Heap.push(machine); 38  } 39 }

 


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