ue4 C++ 生成並彈出一個菜單

FGlobalSettingModule & GSettingMod = FModuleManager :: LoadModuleChecked < FGlobalSettingModule >( TEXT ( "GlobalSetting" ));

               FString userIdStr = FString :: FromInt (GSettingMod. GetUserInfo (). userId );

               FString modelUrl = _ItemModel -> _ItemInfo . modelUrl ;

               if ( modelUrl . Find (userIdStr) == INDEX_NONE )

              {

                      return FReply :: Unhandled ();

              }

               FMenuBuilder MenuBuilder ( true , nullptr );

               MenuBuilder . BeginSection ( "PathFolderMoveCopy" , FText :: FromString ( TEXT ( "硬裝操作" )));

              {

                      MenuBuilder . AddMenuEntry (

                            FText :: FromString ( TEXT ( "刪除" )),

                            FText :: FromString ( TEXT ( "刪除該選項" )),

                            FSlateIcon (),

                            FUIAction ( FExecuteAction :: CreateLambda ([ this ]() { DeleteThisData (); }))

                     );

              }

               MenuBuilder . EndSection ();

              

               TSharedPtr < SWindow > Parent = FSlateApplication :: Get (). GetActiveTopLevelWindow ();

               if ( Parent . IsValid ())

              {

                      FSlateApplication :: Get (). PushMenu (

                            Parent . ToSharedRef (),

                            FWidgetPath (),

                            MenuBuilder . MakeWidget (),

                            FSlateApplication :: Get (). GetCursorPos (),

                             FPopupTransitionEffect ( FPopupTransitionEffect :: ContextMenu )

                     );

              }