ListView (帶分頁)
1.帶分頁效果的基礎模板
1) view
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): model = Company context_object_name = "companies" template_name = 'company/company_list.html' paginate_by = 20
2) url
from django.conf.urls import url from . import views urlpatterns = [ url(r'^$', views.CompanyListView.as_view(), name='company-list'), ]
3) template
<table class="table table-striped"> <thead> <tr> <th>名稱</th> <th>規模</th> </tr> </thead> <tbody> {% for company in companies %} <tr> <td>{{ company.name }}</td> <td>{{ company.scale }}</td> </tr> {% endfor %} </tbody> </table> {% if is_paginated %} <div class="pagination center-block"> <span>共{{ page_obj.paginator.num_pages }}頁</span> <span id="paging" class="step-links" style="display: block;text-align: center"> {% if page_obj.has_previous %} <span><a href="?page={{ page_obj.previous_page_number }}">上一頁</a></span> {% endif %} <span class="active">{{ page_obj.number }}</span> {% if page_obj.has_next %} <span><a href="?page={{ page_obj.next_page_number }}">下一頁</a></span> {% endif %} </span> </div> {% endif %}
2.model < queryset < get_queryset()
這時候,頁面上顯示是model里的所有對象。如果我們希望這個object list排序后呈現呢?或者想要篩選部分呈現?這些又在哪定義呢?
很簡單,這時候只要定義queryset或者重寫get_queryset()方法就能搞定。
注意:model、queryset、get_queryset()至少要定義一個。而當三個都定義的時候,get_queryset()的效果強於queryset,而queryset的效果又強於model。
2.1 定義queryset
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): context_object_name = "companies" template_name = 'company/company_list.html' paginate_by = 20 queryset = Company.objects.all().order_by('-scale')
2.2 重寫get_queryset()
from django.views.generic.list import ListView from employ.models import Company class CompanyListView(ListView): context_object_name = "companies" template_name = 'company/company_list.html' paginate_by = 20
def get_queryset(self): companies = Company.objects.all().order_by('-scale') return companies
3.向template傳遞額外信息
以上,我們只向template中傳遞了關於某個Model里的所有對象。那么,我們有什么方法傳遞更多信息呢?
方法一:重寫get_context_data()。如我想傳遞當前時間顯示在template中:
view:
from django.views.generic.list import ListView from employ.models import Company from datetime import datetime class CompanyListView(ListView): context_object_name = "companies" template_name = 'company/company_list.html' paginate_by = 20 queryset = Company.objects.all().order_by('-open_positions') def get_context_data(self, **kwargs): context = super(CompanyListView, self).get_context_data(**kwargs) context['now'] = datetime.now() return context
template:
{{ now }}
方法二:在view中定義some_method()方法返回數據,在模版中使用{{ view.some_method }}。
注意:some_method(self)方法只能有一個self參數。
view:
from django.views.generic.list import ListView from employ.models import Company from datetime import datetime class CompanyListView(ListView): context_object_name = "companies" template_name = 'company/company_list.html' paginate_by = 20 queryset = Company.objects.all().order_by('-open_positions') def now(self): return datetime.now()
template:
{{ view.now }}