第三題 有如下Student 對象,
private String name;
private int age;
private int score;
private String classNum;
其中,classNum 表示學生的班號,例如“class05”。 有如下List
List list = new ArrayList();
list.add(new Student(“Tom”, 18, 100, “class05”));
list.add(new Student(“Jerry”, 22, 70, “class04”));
list.add(new Student(“Owen”, 25, 90, “class05”));
list.add(new Student(“Jim”, 30,80 , “class05”));
list.add(new Student(“Steve”, 28, 66, “class06”));
list.add(new Student(“Kevin”, 24, 100, “class04”));
在這個list 的基礎上,完成下列要求:
1) 計算所有學生的平均年齡
2) 計算各個班級的平均分 自己想的方法比較復雜暫時沒有寫,后期改善
package Test03; import java.util.ArrayList; import java.util.List; public class TestStudent { public static void main(String[] args) { List <Student> list = new ArrayList<>(); list.add(new Student("Tom", 18, 100,"class05")); list.add(new Student("Jerry", 22, 70,"class04")); list.add(new Student("Owen", 25, 90,"class05")); list.add(new Student("Jim", 30,80 , "class05")); list.add(new Student("Steve", 28, 66, "class06")); list.add(new Student("Kevin", 24, 100, "class04")); int sum = 0; for(int i =0;i<list.size();i++) { sum=sum+list.get(i).getAge(); } System.out.println("平均年齡:"+sum/list.size()); } }