三種去重的方法
1、List中的元素實現IEquatabe接口,並提供Equals方法和GetHashCode方法。
2、使用表達式
users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i)
3、使用循環,判斷每個元素是否重復
using System;
using System.Collections.Generic;
using System.Linq;
namespace NonDuplicateList
{
class Program
{
static void Main(string[] args)
{
List<User> users = new List<User>();
users.Add(new User("張三", "永豐路299號"));
users.Add(new User("張三", "上地西路8號"));//重復項,去重后將刪掉
users.Add(new User("李四", "海鷹路甲一號"));
List<User> nonDuplicateList1 = users.Distinct().ToList();//通過User類的Equals實現去重
List<User> nonDuplicateList2 = users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i).ToList();//Lambda表達式去重
List<User> nonDuplicateList3 = new List<User>();//通過循環方式去重
foreach(User user in users)
{
if(nonDuplicateList3.Exists(x=>x.name==user.name) == false)
{
nonDuplicateList3.Add(user);
}
}
foreach(List<User> list in new Object[]{nonDuplicateList1,nonDuplicateList2,nonDuplicateList3})//打印出三個List的元素
{
Console.Write("nonDuplicateList:\r\n");
foreach(User u in list)
{
Console.WriteLine("\t" + u.ToString());
}
}
Console.Read();
}
}
class User:IEquatable<User>//繼承IEquatable接口,實現Equals方法。List就可以使用Distinct去重
{
public string name { get; set; }
string address;
public User(string _name, string _address)
{
name = _name;
address = _address;
}
public override string ToString()
{
return string.Format("name:{0},\taddress:{1}", name, address);
}
public bool Equals(User other)
{
return this.name == other.name;
}
public override int GetHashCode()
{
return name.GetHashCode();
}
}
}
