三種去重的方法
1、List中的元素實現IEquatabe接口,並提供Equals方法和GetHashCode方法。
2、使用表達式
users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i)
3、使用循環,判斷每個元素是否重復
using System; using System.Collections.Generic; using System.Linq; namespace NonDuplicateList { class Program { static void Main(string[] args) { List<User> users = new List<User>(); users.Add(new User("張三", "永豐路299號")); users.Add(new User("張三", "上地西路8號"));//重復項,去重后將刪掉 users.Add(new User("李四", "海鷹路甲一號")); List<User> nonDuplicateList1 = users.Distinct().ToList();//通過User類的Equals實現去重 List<User> nonDuplicateList2 = users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i).ToList();//Lambda表達式去重 List<User> nonDuplicateList3 = new List<User>();//通過循環方式去重 foreach(User user in users) { if(nonDuplicateList3.Exists(x=>x.name==user.name) == false) { nonDuplicateList3.Add(user); } } foreach(List<User> list in new Object[]{nonDuplicateList1,nonDuplicateList2,nonDuplicateList3})//打印出三個List的元素 { Console.Write("nonDuplicateList:\r\n"); foreach(User u in list) { Console.WriteLine("\t" + u.ToString()); } } Console.Read(); } } class User:IEquatable<User>//繼承IEquatable接口,實現Equals方法。List就可以使用Distinct去重 { public string name { get; set; } string address; public User(string _name, string _address) { name = _name; address = _address; } public override string ToString() { return string.Format("name:{0},\taddress:{1}", name, address); } public bool Equals(User other) { return this.name == other.name; } public override int GetHashCode() { return name.GetHashCode(); } } }