三種去重的方法
1、List中的元素實現IEquatabe接口,並提供Equals方法和GetHashCode方法。
2、使用表達式
- users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i)
去重,這條語句返回結果只保留users這個List中重復的元素的第一個(name相等認為重復)。
3、使用循環,判斷每個元素是否重復
- using System;
- using System.Collections.Generic;
- using System.Linq;
- namespace NonDuplicateList
- {
- class Program
- {
- static void Main(string[] args)
- {
- List<User> users = new List<User>();
- users.Add(new User("張三", "永豐路299號"));
- users.Add(new User("張三", "上地西路8號"));//重復項,去重后將刪掉
- users.Add(new User("李四", "海鷹路甲一號"));
- List<User> nonDuplicateList1 = users.Distinct().ToList();//通過User類的Equals實現去重
- List<User> nonDuplicateList2 = users.Where((x,i)=>users.FindIndex(z=>z.name == x.name) == i).ToList();//Lambda表達式去重
- List<User> nonDuplicateList3 = new List<User>();//通過循環方式去重
- foreach(User user in users)
- {
- if(nonDuplicateList3.Exists(x=>x.name==user.name) == false)
- {
- nonDuplicateList3.Add(user);
- }
- }
- foreach(List<User> list in new Object[]{nonDuplicateList1,nonDuplicateList2,nonDuplicateList3})//打印出三個List的元素
- {
- Console.Write("nonDuplicateList:\r\n");
- foreach(User u in list)
- {
- Console.WriteLine("\t" + u.ToString());
- }
- }
- Console.Read();
- }
- }
- class User:IEquatable<User>//繼承IEquatable接口,實現Equals方法。List就可以使用Distinct去重
- {
- public string name { get; set; }
- string address;
- public User(string _name, string _address)
- {
- name = _name;
- address = _address;
- }
- public override string ToString()
- {
- return string.Format("name:{0},\taddress:{1}", name, address);
- }
- public bool Equals(User other)
- {
- return this.name == other.name;
- }
- public override int GetHashCode()
- {
- return name.GetHashCode();
- }
- }
- }