如：
'ab-cd-ef-gh'
現在要取到，第三個'-'后面的gh
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declare @s varchar(100);
set @s = 'ab-cd-ef-gh';
select right(@s, charindex('-',reverse(@s))-1)
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declare
@str
char
(20)
set
@str=
'ab-cd-ef-gh'
select
stuff(@str,1,len(@str)-charindex(
'-'
,reverse(rtrim(@str)))+1,
''
)
as
result
select
substring
(@str,len(@str)-charindex(
'-'
,reverse(rtrim(@str)))+2,charindex(
'-'
,reverse(rtrim(@str)))-1)
as
result
select
reverse(
left
(reverse(@str),charindex(
'-'
,reverse(@str))-1))
as
result
select
right
(@str,charindex(
'-'
,reverse(@str))-1)
as
result