Table: Person
+-------------+---------+ | Column Name | Type | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId is the primary key column for this table.
Table: Address
+-------------+---------+ | Column Name | Type | +-------------+---------+ | AddressId | int | | PersonId | int | | City | varchar | | State | varchar | +-------------+---------+ AddressId is the primary key column for this table.
Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:
FirstName, LastName, City, State
LeetCode還出了是來到數據庫的題,來那么也來做做吧,這道題是第一道,相對來說比較簡單,是一道兩表聯合查找的問題,我們需要用到Join操作,關於一些Join操作可以看我之前的博客SQL Left Join, Right Join, Inner Join, and Natural Join 各種Join小結,最直接的方法就是用Left Join來做,根據PersonId這項來把兩個表聯合起來:
解法一:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address ON Person.PersonId = Address.PersonId;
在使用Left Join時,我們也可以使用關鍵Using來聲明我們相用哪個列名來進行聯合:
解法二:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address USING(PersonId);
或者我們可以加上Natural關鍵字,這樣我們就不用聲明具體的列,MySQL可以自行搜索相同的列:
解法三:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person NATURAL LEFT JOIN Address;
參考資料:
https://leetcode.com/discuss/21216/its-a-simple-question-of-left-join-my-solution-attached
https://leetcode.com/discuss/53001/comparative-solution-between-left-using-natural-left-join
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