[leetcode]Palindrome Partitioning @ Python

原題地址：https://oj.leetcode.com/problems/palindrome-partitioning/

題意：

Given a string s, partition s such that every substring of the partition is a palindrome.

Return all possible palindrome partitioning of s.

For example, given s = "aab",
Return

  [
    ["aa","b"],
    ["a","a","b"]
  ]

解題思路：回文的分割問題。同樣是需要窮舉出所有符合條件的集合，那么我們還是使用dfs。

代碼：

class Solution:
    # @param s, a string
    # @return a list of lists of string
    def isPalindrome(self, s):
        for i in range(len(s)):
            if s[i] != s[len(s)-1-i]: return False
        return True
    
    def dfs(self, s, stringlist):
        if len(s) == 0: Solution.res.append(stringlist)
        for i in range(1, len(s)+1):
            if self.isPalindrome(s[:i]):
                self.dfs(s[i:], stringlist+[s[:i]])
            
    def partition(self, s):
        Solution.res = []
        self.dfs(s, [])
        return Solution.res