背景:在做項目時,經常會遇到這樣的表結構在主表的中有一列保存的是用逗號隔開ID。如,當一個員工從屬多個部門時、當一個項目從屬多個城市時、當一個設備從屬多個項目時,很多人都會在員工表中加入一個deptIds VARCHAR(1000)列(本文以員工從屬多個部門為例),用以保存部門編號列表(很明顯這不符合第一范式,但很多人這樣設計了,在這篇文章中我們暫不討論在這種應用場景下,如此設計的對與錯,有興趣的可以在回復中聊聊),然后我們在查詢列表中需要看到這個員工從屬哪些部門。
初始化數據:
部門表、員工表數據:

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) DROP TABLE [dbo].Department GO --部門表 CREATE TABLE Department ( id int, name nvarchar(50) ) INSERT INTO Department(id,name) SELECT 1,'人事部' UNION SELECT 2,'工程部' UNION SELECT 3,'管理部' SELECT * FROM Department IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) DROP TABLE [dbo].Employee GO --員工表 CREATE TABLE Employee ( id int, name nvarchar(20), deptIds varchar(1000) ) INSERT INTO Employee(id,name,deptIds) SELECT 1,'蔣大華','1,2,3' UNION SELECT 2,'小明','1' UNION SELECT 3,'小華','' SELECT * FROM Employee
希望得到的結果:
解決方法:
第一步,是得到如下的數據。即將員工表集合與相關的部門集合做交叉連接,其中使用了fun_SplitIds函數(作用是將ids分割成id列表),然后員工集合與這個得到的集合做交叉連接
SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id;
第二步,已經得到了如上的數據,然后要做的就是根據ID分組,並對deptName列做聚合操作,但可惜的是SQL SERVER還沒有提供對字符串做聚合的操作。但想到,我們處理樹形結構數據時,用CTE來做關系數據,做成有樹形格式的數據,如此我們也可以將這個問題轉換成做樹形格式的問題,代碼如下:

;WITH EmployeT AS( --員工的基本信息(使用OUTER APPLY將多個ID拆分開來,然后與部門表相關聯) --此時已將員工表所存的IDS分別與部門相關聯,下面需要將此集合中的deptName聚合成一個記錄 SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id ),mike AS( SELECT id,name,deptIds,deptName ,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num FROM EmployeT ),mike2 AS( SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num FROM mike WHERE level_num=1 UNION ALL SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num FROM mike AS m INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 ),maxMikeByIDT AS( SELECT id,MAX(level_num) AS level_num FROM mike2 GROUP BY ID ) SELECT A.id,A.name,A.deptIds,A.deptName FROM mike2 AS A INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num ORDER BY A.id OPTION (MAXRECURSION 0)
結果如下:
全部SQL:

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) DROP TABLE [dbo].Department GO --部門表 CREATE TABLE Department ( id int, name nvarchar(50) ) INSERT INTO Department(id,name) SELECT 1,'人事部' UNION SELECT 2,'工程部' UNION SELECT 3,'管理部' SELECT * FROM Department IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) DROP TABLE [dbo].Employee GO --員工表 CREATE TABLE Employee ( id int, name nvarchar(20), deptIds varchar(1000) ) INSERT INTO Employee(id,name,deptIds) SELECT 1,'蔣大華','1,2,3' UNION SELECT 2,'小明','1' UNION SELECT 3,'小華','' SELECT * FROM Employee --創建一個表值函數,用來拆分用逗號分割的數字串,返回只有一列數字的表 IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fun_SplitIds]')) DROP FUNCTION [dbo].fun_SplitIds GO CREATE FUNCTION dbo.fun_SplitIds( @Ids nvarchar(1000) ) RETURNS @t_id TABLE (id VARCHAR(36)) AS BEGIN DECLARE @i INT,@j INT,@l INT,@v VARCHAR(36); SET @i = 0; SET @j = 0; SET @l = len(@Ids); while(@j < @l) begin SET @j = charindex(',',@Ids,@i+1); IF(@j = 0) set @j = @l+1; SET @v = cast(SUBSTRING(@Ids,@i+1,@j-@i-1) as VARCHAR(36)); INSERT INTO @t_id VALUES(@v) SET @i = @j; END RETURN; END GO ;WITH EmployeT AS( --員工的基本信息(使用OUTER APPLY將多個ID拆分開來,然后與部門表相關聯) --此時已將員工表所存的IDS分別與部門相關聯,下面需要將此集合中的deptName聚合成一個記錄 SELECT E.*,ISNULL(D.name,'') AS deptName FROM Employee AS E OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID LEFT JOIN Department AS D ON DID.ID=D.id ),mike AS( SELECT id,name,deptIds,deptName ,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num FROM EmployeT ),mike2 AS( SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num FROM mike WHERE level_num=1 UNION ALL SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num FROM mike AS m INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 ),maxMikeByIDT AS( SELECT id,MAX(level_num) AS level_num FROM mike2 GROUP BY ID ) SELECT A.id,A.name,A.deptIds,A.deptName FROM mike2 AS A INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num ORDER BY A.id OPTION (MAXRECURSION 0)