如果將值插入到表的標識列中,需要啟用 SET IDENTITY_INSERT。
舉例如下:
創建表Orders、Products,Orders表與Products表分別有標識列OrderID與ProductID:

1 CREATE TABLE Orders( 2 OrderID INT IDENTITY(1,1) NOT NULL PRIMARY KEY, 3 PriceDate DateTime 4 ) 5 6 CREATE TABLE Products( 7 ProductID INT IDENTITY(1,1) NOT NULL PRIMARY KEY, 8 PriceDate Datetime 9 )
當我們用如下插入語句往Orders表中插入數據:

1 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE())
執行此語句后,會出現如下錯誤:
把插入語句做如下修改:

1 SET IDENTITY_INSERT Orders ON 2 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE())
此時執行成功;
我們在向Products表做如上插入:

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products (ProductID,PriceDate ) VALUES(1,GETDATE())
產生如下錯誤:
我們對sql做如下修改后,products表插入數據成功

1 SET IDENTITY_INSERT Orders ON 2 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE()) 3 SET IDENTITY_INSERT Orders OFF 4 5 SET IDENTITY_INSERT Products ON 6 INSERT INTO Products (ProductID,PriceDate ) VALUES(1,GETDATE()) 7 SET IDENTITY_INSERT Products OFF
可以看到當我們對表的Identity_Insert 的啟用與關閉時成對出現,即

1 SET IDENTITY_INSERT Products ON 2 --Code 3 SET IDENTITY_INSERT Products OFF
如果我們用下面的語句往Products表中插入數據

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products SELECT * FROM Orders 3 SET IDENTITY_INSERT Products OFF
出現如下錯誤:
修改上面t-sql語句:

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products(ProductID,PriceDate) SELECT * FROM Orders 3 SET IDENTITY_INSERT Products OFF
可以知道如果對標識列進行插入,那么需要顯示的列出標識列