如果将值插入到表的标识列中,需要启用 SET IDENTITY_INSERT。
举例如下:
创建表Orders、Products,Orders表与Products表分别有标识列OrderID与ProductID:

1 CREATE TABLE Orders( 2 OrderID INT IDENTITY(1,1) NOT NULL PRIMARY KEY, 3 PriceDate DateTime 4 ) 5 6 CREATE TABLE Products( 7 ProductID INT IDENTITY(1,1) NOT NULL PRIMARY KEY, 8 PriceDate Datetime 9 )
当我们用如下插入语句往Orders表中插入数据:

1 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE())
执行此语句后,会出现如下错误:
把插入语句做如下修改:

1 SET IDENTITY_INSERT Orders ON 2 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE())
此时执行成功;
我们在向Products表做如上插入:

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products (ProductID,PriceDate ) VALUES(1,GETDATE())
产生如下错误:
我们对sql做如下修改后,products表插入数据成功

1 SET IDENTITY_INSERT Orders ON 2 INSERT INTO Orders (OrderID ,PriceDate ) VALUES(1,GETDATE()) 3 SET IDENTITY_INSERT Orders OFF 4 5 SET IDENTITY_INSERT Products ON 6 INSERT INTO Products (ProductID,PriceDate ) VALUES(1,GETDATE()) 7 SET IDENTITY_INSERT Products OFF
可以看到当我们对表的Identity_Insert 的启用与关闭时成对出现,即

1 SET IDENTITY_INSERT Products ON 2 --Code 3 SET IDENTITY_INSERT Products OFF
如果我们用下面的语句往Products表中插入数据

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products SELECT * FROM Orders 3 SET IDENTITY_INSERT Products OFF
出现如下错误:
修改上面t-sql语句:

1 SET IDENTITY_INSERT Products ON 2 INSERT INTO Products(ProductID,PriceDate) SELECT * FROM Orders 3 SET IDENTITY_INSERT Products OFF
可以知道如果对标识列进行插入,那么需要显示的列出标识列