You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them ...
Given a stringSof lowercase letters, aduplicate removalconsists of choosing two adjacent and equal letters, and removingthem. We repeatedly make duplicate removals on S until we no longer can. Return ...
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You are given a string s and an integer k, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them ...
這是小川的第389次更新,第419篇原創 01 看題和准備 今天介紹的是LeetCode算法題中Easy級別的第251題(順位題號是1047)。給定一個小寫字母的字符串S,重復刪除兩個相鄰且相等的字母。 我們在S上反復刪除,直到我們再也無法刪除。 在完成所有此類重復刪除后返回最后一個字符串 ...
In a string composed of 'L', 'R', and 'X' characters, like "RXXLRXRXL", a move consists of either replacing one occurrence of "XL" with "LX ...
Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only ...
Find all the elements that appear twice in this array ...
Let's define a function `countUniqueChars(s)` that returns the number of unique characters on `s`, for example if `s = "LEETCODE"` then `"L"`, `"T ...
之前通過比較的笨的方法,判斷列表(list)中所有元素是否包含在字符串(string)中,后來發現可以用all()來判斷,查找了一些資料,寫出來發現很簡單,下面分享一下代碼。 1、判斷列表 ...
之前通過比較的笨的方法,判斷列表(list)中所有元素是否包含在字符串(string)中,后來發現可以用all()來判斷,查找了一些資料,寫出來發現很簡單,下面分享一下代碼。 原文地址:Python 通過all()判斷列表(list)中所有元素是否都包含某個字符串(string) ...