D. 0-1 MST Ujan has a lot of useless stuff in his drawers, a considerable part of which are his mat ...
B . Character Swap Hard Version This problem is different from the easy version. In this version Ujan makes at most swaps. In addition, , and it is necessary to print swaps themselves. You can hack th ...
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D. 0-1 MST Ujan has a lot of useless stuff in his drawers, a considerable part of which are his mat ...
C. Tile Painting Ujan has been lazy lately, but now has decided to bring his yard to good shape. Fi ...
F2. Wrong Answer on test 233 (Hard Version) Your program fails again. This time it gets "Wrong answer on test 233" . This is the harder version ...
😢 😢 😢 題意:第 i 步可以挑一個數字加 i ,問你最少多少步能讓兩個數字相等 假設剛開始兩個數字相等,然后一個數字向前走了abs(b-a)步,由等差數列求和公式,這時候我們貪心的讓另外一個數字走大於等於abs(b - a)的最小步數,然后如果兩數相等必須滿足走的步數之和 ...
Codeforces Round #599 (Div. 2) D. 0-1 MST Description Ujan has a lot of useless stuff in his drawers, a considerable part of which are his math ...
B. Strange List 題目分析 題意:給你一個長度為n的數組和一個數字x,從第一個元素開始,如果改元素q能被x整除,那么將就在數組后面新增x個(q / x),直到遇到的元素不能被x整除,求最后數組的元素之和 讓我們從樣例開始入手分析:樣例中的第一個情況數組a為[12],x為2,數組 ...
題目鏈接 A. Trip for Meal 題意 三個點之間兩兩有路徑,分別長為\(a,b,c\),現在從第一個點出發,走\(n-1\)條邊,問總路徑最小值。 思路 記起始點相鄰的邊為\(a,b\),相對的邊為\(c\). 首先肯定走\(a,b\)中的最小值(不妨設為\(a\)),到達 ...
codeforces-1287-A A. Angry Students time limit per test ...