leetcode 850. Rectangle Area II
給定一些矩形2 求覆蓋面積 矩形不超過200個 1# 算法1 朴素思想 雖然朴素但是代碼卻有意思 利用容斥原理 復雜度高達 N*2^N 2# 點位壓縮，壓縮后進行暴力循環 同時壓縮x和y 最后返回 N^3 3# 算法3 掃描線算法 將每一個矩形看作一個 "事件" 這樣的事件 ...
原文：[LeetCode] 850. Rectangle Area II 矩形面積之二
We are given a list of axis aligned rectangles . Each rectangle i x , y , x , y , where x , y are the coordinates of the bottom left corner, and x , y are the coordinates of the top right corner of t ...
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