[LeetCode] 850. Rectangle Area II 矩形面積之二
We are given a list of (axis-aligned) `rectangles`. Each `rectangle[i] = [x1, y1, x2, y2] `, where (x1, y1) are the coordinates of the bottom-left ...
原文：leetcode 850. Rectangle Area II
給定一些矩形 求覆蓋面積 矩形不超過 個 算法 朴素思想 雖然朴素但是代碼卻有意思 利用容斥原理 復雜度高達 N N 點位壓縮，壓縮后進行暴力循環 同時壓縮x和y 最后返回 N 算法 掃描線算法 將每一個矩形看作一個 事件 這樣的事件 注意到剛才的 算法中使用了 區間維護的算法 這里使用線段樹維護這個區間 使得達到 NlogN 下面是py 實現線段樹 注意這里的 下標實際意義不是 容器 而是 標志 ...
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