題目 題目鏈接 Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. ...
復習一下KMP算法 KMP的主要思想是利用字符串自身的前綴后綴的對稱性,來構建next數組,從而實現用接近O N 的時間復雜度完成字符串的匹配 對於一個字符串str,next j k 表示滿足str ...k str j k...j 的最大的k,即對於子串str ...j ,前k個字母等於后k個字母 現在求解str的next數組: 初始化:next 那么在知道了next j 的情況下,如何遞推地求 ...
2016-12-03 19:32 0 1538 推薦指數:
題目 題目鏈接 Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies of the substring together. ...
Given a non-empty string check if it can be constructed by taking a substring of it and appending multiple copies ...
Given a string text, we are allowed to swap two of the characters in the string. Find the length of the longest substring with repeated characters. ...
題目鏈接 Given a string S and a string T, find the minimum window in S which will contain all the chara ...
useful to identify repeated sequences within the DNA. W ...
Given a string S and a string T, find the minimum window in S which will contain all the characters ...
Problem Description: Given a pattern and a string str, find if str follows the same pattern. Here follow means a full match ...
兩種解法,動態規划和KMP變種 動態規划,類似於lcs的解法,數組flag[i][j]記錄s從i到j是不是回文 首先初始化,i>=j時,flag[i][j]=true,這是因為s[i][i]是單字符的回文,當i>j時,為true,是因為有可能出現flag[2][1]這種情況 ...